小白求指点:自定义函数内调用另外一个函数里的全局变量,该怎么写啊

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Release: 2016-06-23 13:34:16
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member.inc.php:

function marrbase(){if(isset($_COOKIE["uname"]) && isset($_COOKIE["uid"])){global $mbase;$mbase_data = mysql_query("select * from dh_member where `id`=" . $_COOKIE["uid"] . " and `mck`=1");if (!$mbase_data){die(mysql_error());exit();}$mbase = mysql_fetch_array($mbase_data);}else{exit();}}
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我是这样写的:
require_once("member.inc.php");function supp(){marrbase();echo $mbase["email"]; exit();}
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输出为空,小白求大神指点一下这个该怎么写才规范正确啊..


回复讨论(解决方案)

function supp() {
global $mbase;
marrbase();
echo $mbase["email"]; exit();
}

function supp() {
global $mbase;
marrbase();
echo $mbase["email"]; exit();
}





谢谢啊,我还是有个小疑问:

我现在是在supp()里面调用的,但是我在其他页面输出的时候 直接echo $mbase["email"]; exit(); 又能输出值
这是怎么回事啊?

因为你在函数里有 global $mbase;
所以 $mbase 就是全局变量了
只要你执行过 marrbase 函数
$mbase 就可在函数外访问了

但这样的写法并不符合软件工程学中 低耦合 的要求

因为你在函数里有 global $mbase;
所以 $mbase 就是全局变量了
只要你执行过 marrbase 函数
$mbase 就可在函数外访问了

但这样的写法并不符合软件工程学中 低耦合 的要求



那该怎么写 才正规啊

作为参数传递

作为参数传递?

怎么设计啊

function marrbase(){  ....  return $mbase;}function supp() {  $mbase = marrbase();  echo $mbase["email"];}
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function marrbase(&$mbase){  ....  $mbase = ....;}function supp() {  marrbase($mbase);  echo $mbase["email"];}
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function marrbase(){  ....  return $mbase;}function supp() {  $mbase = marrbase();  echo $mbase["email"];}
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function marrbase(&$mbase){  ....  $mbase = ....;}function supp() {  marrbase($mbase);  echo $mbase["email"];}
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非常感谢~~受教了 谢谢
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