怎样使用php获取复杂json数据并输出
这是调用多客服查看当前在线客服时的微信api
返回数据示例(正确时的JSON返回结果):
{ "kf_online_list": [ { "kf_account": "test1@test", "status": 1, "kf_id": "1001", "auto_accept": 0, "accepted_case": 1 }, { "kf_account": "test2@test", "status": 1, "kf_id": "1002", "auto_accept": 0, "accepted_case": 2 } ]}
以下是我的代码:
$url_online ="https://api.weixin.qq.com/cgi-bin/customservice/getonlinekflist?access_token={$access_token}";$output_online=file_get_contents($url_online);$jsonStr = json_decode($output_online,true);//读取信息:$content = "客服1:".$jsonStr["kf_online_list"]["kf_account"]."\n在线状态:".$jsonStr["kf_online_list"]["status"]."\n正在接待人数:".$jsonStr["kf_online_list"]["accepted_case"]."\n\n客服2:".$jsonStr["kf_online_list"]["kf_account"]."\n在线状态:".$jsonStr["kf_online_list"]["status"]."\n正在接待人数:".$jsonStr["kf_online_list"]["accepted_case"];?>
我本是希望获得所有的kf_account数据,并返回到微信回话界面,可是这结构有点复杂,还有相同的字段。。。
目前还查询不到结果,我估计是最后获取json的数组写的不对,希望大家帮忙!
回复讨论(解决方案)
file_get_contents对https使用貌似有个警告,你需要打开display errors才能看到
这种问题一步步var_dump上一个变量就可以确定位置了
额知道为啥了,在$
jsonStr["kf_online_list"]["kf_account"]
jsonStr["kf_online_list"][0]["kf_account"]
print_r($data);
看看decode後的????,就不容易?了。
二维数组当做一维访问,当然就不行啦
$status=array('0'=>'不在线','1'=>'电脑在线','2'=>'手机在线','3'=>'电脑手机在线');//$onlinestatus=$jsonStr["kf_online_list"][0]["status"];foreach ($jsonStr['kf_online_list'] as $list){ foreach ($list[kf_account] as $account) { foreach ($list[status] as $onlinestatus) { $statusStr0=$status[$onlinestatus]; foreach ($list[accepted_case] as $jiedai) { $content.="客服:".$account."\n在线状态:"."$statusStr0"."\n正在接待人数:"."$jiedai"."\n\n"; } } }}
这是我又写的代码,在foreach ($list[kf_account] as $account)这一行出错了
错误:Invalid argument supplied for foreach() ,这又怎么改呢亲们?
干脆用for循环得了。。
$s =<<< JSON{ "kf_online_list": [ { "kf_account": "test1@test", "status": 1, "kf_id": "1001", "auto_accept": 0, "accepted_case": 1 }, { "kf_account": "test2@test", "status": 1, "kf_id": "1002", "auto_accept": 0, "accepted_case": 2 } ]}JSON;$jsonStr = json_decode($s, true);$content = '';foreach($jsonStr['kf_online_list'] as $i=>$item) { $n = $i + 1; $content .= "客服{$n}:$item[kf_account]在线状态:$item[status]正在接待人数:$item[accepted_case]";}echo $content;
客服1:test1@test在线状态:1正在接待人数:1客服2:test2@test在线状态:1正在接待人数:2

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