一个0开头的数据循环累加的问题
今天要批量生成一批合同号,遇到问题了,比如说
start=0066812~end=0066818
for ($start;$start 除了0066812之外,后面的全将00给去掉了,请问有什么方法可以保留住0的??
回复讨论(解决方案)
$start = 66812;$end = 66818;for ($start;$start<=$end;$start++){ $s = sprintf('%07d', $start); echo $s . '<br>';}
0066812006681300668140066815006681600668170066818
$start = 66812;$end = 66818;for ($start;$start<=$end;$start++){ $s = sprintf('%07d', $start); echo $s . '<br>';}
0066812006681300668140066815006681600668170066818
赋值的时候一定要是
$start = 0066812;
$end = 0066818;
前边有两个0
因为还有种可能是009999到010000,反正09过了就是10,前边就不是两个0了
有什么区别吗?
$start = '0066812';$end = '0066818'; for ($start;$start<=$end;$start++){ $s = sprintf('%07d', $start); echo $s . '<br>';}
0066813
0066814
0066815
0066816
0066817
0066818
但是如果写作 $start = 0066812;
那就是八进制数,全完蛋了
有什么区别吗?
$start = '0066812';$end = '0066818'; for ($start;$start<=$end;$start++){ $s = sprintf('%07d', $start); echo $s . '<br>';}
0066813
0066814
0066815
0066816
0066817
0066818
但是如果写作 $start = 0066812;
那就是八进制数,全完蛋了
谢谢,讲得非常好,大师太好了

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