求一段根据日期隔行显示内容列表的PHP代码
<?php $sql = mysql_query("select title,times from table order by times desc limit 0,50"); while($row=mysql_fetch_array($sql)){ //每个日期只显示一次 echo "<h2 id="row-times">".$row['times']."</h2>"; //该日期发布的全部内容 echo "<li>".$row['title']."</li>"; }?>
显示方式如下
12-30
12-30发布的内容1
12-30发布的内容2
12-30发布的内容3
12-30发布的内容4
12-30发布的内容5
12-29
12-29发布的内容1
12-29发布的内容2
12-29发布的内容3
12-29发布的内容4
12-29发布的内容5
12-28
12-29发布的内容1
12-29发布的内容2
12-29发布的内容3
12-29发布的内容4
12-29发布的内容5
回复讨论(解决方案)
<?php $sql = mysql_query("select title,times from table order by times desc limit 0,50"); $init_time=""; while($row=mysql_fetch_array($sql)){ if($init_time==''){ //第一次循环 显示时间和第一条信息类容 $init_time=$row['times']; echo "<h2 id="row-times">".$row['times']."</h2>"; echo "<li>".$row['title']."</li>"; }else{ //不是第一条判断 时间与上一条是否相等 if($init_time==$row['times']){ //相等的话说明是同一时间段的 直接打印内容 echo "<h2 id="row-title">".$row['title']."</h2>"; }else{ //不一样 打印时间 和 内容 echo "<h2 id="row-times">".$row['times']."</h2>"; //该日期发布的全部内容 echo "<li>".$row['title']."</li>"; } } }?>
在你的代码基础上改了下,可以试试。

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