很菜的前后台交互程序，用jq,ajax，json格式，

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Release： 2016-06-23 13:43:26

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前台输意一个数字，后台处理，比如加2，再返回前台，求教。请别嘲笑。

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html代码部分：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>无标题文档</title><script src="http://cloud.xing-xing.com/jquery.js"></script><script type="text/javascript" language="javascript">$(function(){	$.get('handle.php',{num:1},function(data){		$("div").html(data);//在div里面输出3	})	})</script></head><body><div></div></body></html>

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handle.php代码部分：

<?phpecho $_GET['num']+2;?>

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很菜的前后台交互程序，用jq ajax，json格式，

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