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时间差问题

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Release: 2016-06-23 13:48:11
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$a=2014-09-30 23:21:55
$b=18:00

请问怎么算出来$a中的23:21与$b的差是多少分钟?


回复讨论(解决方案)

自己弄好了!!!

$d = new datetime(date('H:i:s', strtotime('2014-09-30 23:21:55')));$t = $d->diff(new datetime('18:00:0'));echo $t->format('%H:%I:%S  ');echo $t->h * 60 + $t->i + $t->s / 60;
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05:21:55 321.91666666667

$seconds= (strtotime("2014-09-30 23:21:55")-strtotime("18:00")+86400)%86400;$minutes = floor($seconds/60);var_dump($minutes);
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参考函数:strtotime

或者百度'计算时间差'

假如:
kq.kq_time的值为2014-09-30 23:21:55
kq_c.am_on的值为18:00

怎样使下面的MYSQL语句成立?
$sql_where .=" and DATE_FORMAT(kq.kq_time,'%H:%i')>kq_c.am_on";

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