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回复讨论(解决方案)

php代码问题

Jun 23, 2016 pm 01:52 PM
php code

1.   2.  $id = isset($_POST['id'])? $_POST['id'] : 0;
3.  $filename = 'http://saberlily-images.stor.sinaapp.com/' .strval($id). '.jpg';
4.  if(file_exists($filename)){
5.      echo 'php代码问题';
6.  }else{
7.     echo 'php代码问题';
8.  }
9.  ?>


这段代码中     第3行的filename   函数引用的这段代码有什么问题??? 我把路径改成本地却能访问到
但是  "http://saberlily-images.stor.sinaapp.com/load.jpg  这个路径是没问题的,
因为第7行能成功访问到。
问题出在哪儿

求解,谢谢了!


回复讨论(解决方案)

file_exists 就只能检查本地文件,远程用get_headers获取头信息来判断,你这个需求在php代码问题

var_dump(file_exists('http://saberlily-images.stor.sinaapp.com/load.jpg'));
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打印出来为false;
话说file_exists貌似只能用来判断webroot下面的。

$id = isset($_POST['id'])? $_POST['id'] : 0;$filename = 'http://saberlily-images.stor.sinaapp.com/load.jpg';if(getimagesize($filename)){	echo '11<img  src="/static/imghw/default1.png"  data-src="'.$filename.'"  class="lazy"  .$filename.'"    style="max-width:90%" height="auto" alt="php代码问题" >';}else{	echo '<img  src="/static/imghw/default1.png"  data-src="http://saberlily-images.stor.sinaapp.com/load.jpg"  class="lazy"      style="max-width:90%" height="auto" alt="php代码问题" >';}
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'php代码问题';
外面是单引号,$filename是不能解析的

file_exists只适用于本机或者网络共享文件夹的文件。

file_exists只能判?本地的,判?http的不行。

<?php$filename = '/path/to/foo.txt';if (file_exists($filename)) {    echo "The file $filename exists";} else {    echo "The file $filename does not exist";}?>
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http://cn2.php.net/file_exists

要判??程文件是否存在可以???
function check_remote_file($url){	$result = get_headers($url, 1);	if($result[0]=='HTTP/1.1 200 OK'){		return true;	}else{		return false;	}}$id = isset($_POST['id'])? $_POST['id'] : 0;$filename = 'http://saberlily-images.stor.sinaapp.com/' .strval($id). '.jpg';if(check_remote_file($filename)){    echo '<img  src="/static/imghw/default1.png"  data-src=".$filename."  class="lazy"      style="max-width:90%" height="auto" alt="php代码问题" >';}else{   echo '<img  src="/static/imghw/default1.png"  data-src="http://saberlily-images.stor.sinaapp.com/load.jpg"  class="lazy"      style="max-width:90%" height="auto" alt="php代码问题" >';}
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现在我在Dream Weaver能完美运行了,可是上传到SAE服务器上就不显示了。是什么情况

查看下源码,看生成了什么。

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