php 数组相加,看不懂,请些一个好例子给我看一下好吗
$a ="a";$b ="b";$ay[$a][$b][]= 3;print_r($ay);
输出, Array ( [a] => Array ( [b] => Array ( [0] => 3 ) ) ),意思是不是数组a中存在数组b,数组b中存在一个数组,该数组索引0的时候值是3 。
//////////////////////////////////////
$Me[$a][$b] += $Me[$k][$c]; //请问这个相加之后左边的值会变成什么样??
$Me[$z][$m] = $Me[$sy][$my]; //这个赋值之后会变成怎么样??
这两句,看得我头很大,请帮忙,最好写一个例子给我演示一下这两句,我头脑真的不太好用。。
我只懂得下面这样简单的。。
$a[] =1;
$b[] =2;
echo $a[0] + b[0];结果是3 。
也懂得
$a[] =1;
$b[] =2;
echo $a[0] = b[0]; 结果a[0]是2;
回复讨论(解决方案)
$Me[$a][$b] += $Me[$k][$c]; //请问这个相加之后左边的值会变成什么样??
$Me[$z][$m] = $Me[$sy][$my]; //这个赋值之后会变成怎么样??
这是二维数组的表示法,表示一个元素的值,你大可以当作一个变量:
$a += 1;
$a = 3;
这样就能看懂了吧
$Me[$a][$b] += $Me[$k][$c]; //请问这个相加之后左边的值会变成什么样??
这是简写,等同
$Me[$a][$b] = $Me[$a][$b]+$Me[$k][$c];
等同
$a=$a+$b;
$Me[$z][$m] = $Me[$sy][$my]; //这个赋值之后会变成怎么样??
$Me[$z][$m]和$Me[$sy][$my]都是存放一个值的位置
假如$Me[$z][$m]存放的值为1,$Me[$sy][$my]存放的值为2
那么 echo $Me[$z][$m] = $Me[$sy][$my];
结果就是 $Me[$z][$m]是2
php array() 是多维数组,
1维的取值方式是:array[]
2维的取值方式是:array[][]
以此类推。
可以这样返回数组的维度。
/** * 返回数组的维度 * @param [type] $arr [description] * @return [type] [description] */function arrayLevel($arr){ $al = array(0); function aL($arr,&$al,$level=0){ if(is_array($arr)){ $level++; $al[] = $level; foreach($arr as $v){ aL($v,$al,$level); } } } aL($arr,$al); return max($al); } $arr = array( '0'=>'0', ); echo arrayLevel($arr);
合并数组建议采用php array自带的函数 array_merge() http://www.w3school.com.cn/php/func_array_merge.asp
多动手,少动眼,记得给脑子加点油
$Me = array( array(1, 2, 3, 4), array(4, 6, 7, 8), array(9, 10, 11, 12), array(13, 14, 15, 16),);$a = 0;$b = 1;$k = 2;$c = 3;$z = 3;$m = 3;$sy = 1;$my = 2;$Me[$a][$b] += $Me[$k][$c];$Me[$z][$m] = $Me[$sy][$my];print_r($Me);
懂了,谢谢各位牛人

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