Home > Backend Development > PHP Tutorial > 如何从Json中取出数据放到一个新组中

如何从Json中取出数据放到一个新组中

WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB
Release: 2016-06-23 13:55:35
Original
1101 people have browsed it

JSON数据如下:

{    "CommunityModel": [        {            " UUID ": "xxxxxx-xxxxxx-xxxxxxx-xxxxxx1",            " CommunityName ": "格林花园",            " CommunityAddress ": "XXXX203号",            " Longitude ": "12.33333333",            " Latitude ": "143.1121222",            " Form ": "商品房",            " BuildingNum ": "100",            " OwnerNum ": "1800",            " CarportNum ": "1800"        },{            " UUID ": "xxxxxx-xxxxxx-xxxxxxx-xxxxxx2",            " CommunityName ": "格林花园2",            " CommunityAddress ": "XX路203号",            " Longitude ": "12.33333333",            " Latitude ": "143.1121222",            " Form ": "商品房",            " BuildingNum ": "100",            " OwnerNum ": "1800",            " CarportNum ": "1800"        }    ]}
Copy after login

通过PHP获取,要求获取JSON中UUID和CommunityName放到一个新数组$arr中返回。

我的代码如下:
		                $url_get ='http://api.com:90/1.php';		$json=json_decode($this->curlGet($url_get));		foreach($json as $jsonvalue)		{                      。。。。这里该如何写	//		dump($jsonvalue);		}
Copy after login


回复讨论(解决方案)

好奇怪,居然键名两端是空格

$s =<<< JSON{    "CommunityModel": [        {            " UUID ": "xxxxxx-xxxxxx-xxxxxxx-xxxxxx1",            " CommunityName ": "格林花园",            " CommunityAddress ": "XXXX203号",            " Longitude ": "12.33333333",            " Latitude ": "143.1121222",            " Form ": "商品房",            " BuildingNum ": "100",            " OwnerNum ": "1800",            " CarportNum ": "1800"        },{            " UUID ": "xxxxxx-xxxxxx-xxxxxxx-xxxxxx2",            " CommunityName ": "格林花园2",            " CommunityAddress ": "XX路203号",            " Longitude ": "12.33333333",            " Latitude ": "143.1121222",            " Form ": "商品房",            " BuildingNum ": "100",            " OwnerNum ": "1800",            " CarportNum ": "1800"        }    ]}JSON;$a = json_decode($s, 1);foreach($a['CommunityModel'] as $v) {  $arr[] = array('UUID' => $v[' UUID '], 'CommunityName' => $v[' CommunityName ']);}print_r($arr);
Copy after login
Array(    [0] => Array        (            [UUID] => xxxxxx-xxxxxx-xxxxxxx-xxxxxx1            [CommunityName] => 格林花园        )    [1] => Array        (            [UUID] => xxxxxx-xxxxxx-xxxxxxx-xxxxxx2            [CommunityName] => 格林花园2        ))
Copy after login

 $val[' UUID '],        'CommunityName' => $val[' CommunityName ']    );}print_r($arr);?>
Copy after login

Related labels:
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Issues
ubuntu mongodb 出现 exception: connect failed
From 1970-01-01 08:00:00
0
0
0
git出错: Cannot save the current index state
From 1970-01-01 08:00:00
0
0
0
An error occurred
From 1970-01-01 08:00:00
0
0
0
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template