php查询mysql 多条件判断输出显示
背景:
从mysql查询各字段值输出并且按照条件用红色字体显示满足条件字段值。
条件:
1.syntime小于当前前一周时间的话显示红色。
2.A字段为"无"的话,显示红色。
3.B字段为"无"的话,显示红色。
图一数据库结构:
图二数据库各字段值:
我的代码:(我只满足了第一个条件,其余两个条件不知道该怎么来写)
$sql = "select username, onoff, intime, syntime, device, a,b,person,dtime from cdmobile order by username desc ";
$rst = mysql_query($sql);
while($row=mysql_fetch_array($rst)){
$nowtime=strtotime('+7 day');
$syntime=strtotime($row['syntime']) ;
if($nowtime>=$syntime){
echo "
}
else
echo "
}
请各位大婶帮忙完善一下代码。要能同时满足三个条件的,并且能正确输出,该显示红色的地方显示红色。以下是目前的结果:
回复讨论(解决方案)
echo "<tr><td>{$row['username']}</td><td>{$row['onoff']}</td><td>{$row['intime']}</td><td>";if ($nowtime>=$syntime) echo "<td style='color:red'>{$row['syntime']}</td>";else echo "<td>{$row['syntime']}</td>";echo "</td><td>{$row['device']}</td><td>";if ($row['a' ]== "无") echo "<td style='color:red'>{$row['a']}</td>";else echo "<td>{$row['a']}</td>";if ($row['b' == "无"]) echo "<td style='color:red'>{$row['a']}</td>";else echo "<td>{$row['b']}</td>";echo "<td>{$row['person']}</td><td>{$row['dtime']}</td></tr>";
echo "<tr><td>{$row['username']}</td><td>{$row['onoff']}</td><td>{$row['intime']}</td>";if ($nowtime>=$syntime) echo "<td style='color:red'>{$row['syntime']}</td>";else echo "<td>{$row['syntime']}</td>";echo "<td>{$row['device']}</td><td>";if ($row['a' ]== "无") echo "<td style='color:red'>{$row['a']}</td>";else echo "<td>{$row['a']}</td>";if ($row['b'] == "无") echo "<td style='color:red'>{$row['b']}</td>";else echo "<td>{$row['b']}</td>";echo "<td>{$row['person']}</td><td>{$row['dtime']}</td></tr>";
纠正下
不对,错位了。
正确了。感谢。自己多添加了括号,画蛇添足了。感谢感谢!
$syntime_style = $nowtime>=$syntime ? ' styly="color:red"' : '';
$a_style = $row['a'] == '无' ? ' styly="color:red"' : '';
$b_style = $row['b'] == '无' ? ' styly="color:red"' : '';
echo "

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