Home > Web Front-end > JS Tutorial > Example of JavaScript implementation of converting Gregorian calendar to lunar calendar function_javascript skills

Example of JavaScript implementation of converting Gregorian calendar to lunar calendar function_javascript skills

PHP中文网
Release: 2016-05-16 19:13:16
Original
1600 people have browsed it

This article mainly introduces JavaScript to realize the function of converting Gregorian calendar to lunar calendar, involving JavaScript date and time related operations and calculation operation skills. Friends in need can refer to it

This article describes the example of JavaScript to realize the function of converting Gregorian calendar to lunar calendar. . Share it with everyone for your reference, the details are as follows:

Complete code (the source code is formatted using the online tool http://www.php.cn/ to make it easier for readers to read ):

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>公历转农历</title>
<script type="text/javascript" language="javascript" >
var CalendarData = new Array(20);
var madd = new Array(12);
var TheDate;
var tgString = "甲乙丙丁戊己庚辛壬癸";
var dzString = "子丑寅卯辰巳午未申酉戌亥";
var numString = "一二三四五六七八九十";
var monString = "正二三四五六七八九十冬腊";
var weekString = "日一二三四五六";
var sx = "鼠牛虎兔龙蛇马羊猴鸡狗猪";
var cYear;
var cMonth;
var cDay;
var cHour;
var cDateString;
var DateString;
var Browser = navigator.appName;
function init() {
  CalendarData[0] = 0x41A95; //公元2001年;
  CalendarData[1] = 0xD4A;
  CalendarData[2] = 0xDA5;
  CalendarData[3] = 0x20B55;
  CalendarData[4] = 0x56A;
  CalendarData[5] = 0x7155B;
  CalendarData[6] = 0x25D;
  CalendarData[7] = 0x92D;
  CalendarData[8] = 0x5192B;
  CalendarData[9] = 0xA95;
  CalendarData[10] = 0xB4A;
  CalendarData[11] = 0x416AA;
  CalendarData[12] = 0xAD5;
  CalendarData[13] = 0x90AB5;
  CalendarData[14] = 0x4BA;
  CalendarData[15] = 0xA5B;
  CalendarData[16] = 0x60A57;
  CalendarData[17] = 0x52B;
  CalendarData[18] = 0xA93;
  CalendarData[19] = 0x40E95;
  madd[0] = 0;
  madd[1] = 31;
  madd[2] = 59;
  madd[3] = 90;
  madd[4] = 120;
  madd[5] = 151;
  madd[6] = 181;
  madd[7] = 212;
  madd[8] = 243;
  madd[9] = 273;
  madd[10] = 304;
  madd[11] = 334; //今年某月已过天数!
}
function GetBit(m, n) {
  return (m >> n) & 1;
} //n月是大月还是小月?
function getInfo() { //用户输入日期!
  var arr = [];
  strData = prompt("请输入年 月 日,并以空格隔开!", "");
  if (strData == null || strData == "") {
    alert("输入错误!请刷新!");
    return false;
  }
  arr = strData.split(" ");
  y = arr[0];
  m = arr[1] - 1;
  d = arr[2];
  TheDate = new Date(y, m, d);
} //getinfo();
function e2c() {
  getInfo();
  var total, m, n, k;
  var isEnd = false;
  var tmp = TheDate.getYear();
  if (tmp < 1900) tmp += 1900; //无用!
  total = (tmp - 2001) * 365 + Math.floor((tmp - 2001) / 4) + madd[TheDate.getMonth()] + TheDate.getDate() - 23; //2001年1月23是除夕;该句计算到起始年正月初一的天数
  if (TheDate.getYear() % 4 == 0 && TheDate.getMonth() > 1) total++; //当年是闰年且已过2月再加一天!
  for (m = 0;; m++) {
    k = (CalendarData[m] < 0xfff) ? 11 : 12; //起始年+m闰月吗?
    for (n = k; n >= 0; n--) {
      if (total <= 29 + GetBit(CalendarData[m], n)) //已找到农历年!
      {
        isEnd = true;
        break;
      }
      total = total - 29 - GetBit(CalendarData[m], n); //寻找农历年!
    }
    if (isEnd) break;
  }
  cYear = 2001 + m; //农历年
  cMonth = k - n + 1; //农历月
  cDay = total; //农历日
  if (k == 12) //闰年!
  {
    if (cMonth == Math.floor(CalendarData[m] / 0x10000) + 1) //该月就是闰月!
    cMonth = 1 - cMonth;
    if (cMonth > Math.floor(CalendarData[m] / 0x10000) + 1) cMonth--; //该月是闰月后某个月!
  }
  cHour = Math.floor((TheDate.getHours() + 1) / 2);
}
function GetcDateString() {
  var tmp = "";
  tmp += tgString.charAt((cYear - 4) % 10);
  //年干
  tmp += dzString.charAt((cYear - 4) % 12); //年支
  tmp += "年(";
  tmp += sx.charAt((cYear - 4) % 12);
  tmp += ")";
  if (cMonth < 1) {
    tmp += "闰";
    tmp += monString.charAt( - cMonth - 1); // 闰几月!
  } else tmp += monString.charAt(cMonth - 1);
  tmp += "月";
  tmp += (cDay < 11) ? "初": ((cDay < 20) ? "十": ((cDay < 30) ? "廿": "卅")); // 初几!
  if (cDay % 10 != 0 || cDay == 10) tmp += numString.charAt((cDay - 1) % 10);
  if (cHour == 12) tmp += "夜";
  tmp += dzString.charAt((cHour) % 12);
  tmp += "时"; //几时!
  cDateString = tmp;
  return tmp;
}
function GetDateString() //公历时间!
{
  var tmp = "";
  var t1 = TheDate.getYear();
  if (t1 < 1900) t1 += 1900;
  tmp += t1 + "-" + (TheDate.getMonth() + 1) + "-" + TheDate.getDate() + " " + TheDate.getHours() + ":" + ((TheDate.getMinutes() < 10) ? "0": "") + TheDate.getMinutes() + " 星期" + weekString.charAt(TheDate.getDay());
  DateString = tmp;
  return tmp;
}
function cnCanlender() {
  init();
  e2c();
  GetDateString();
  GetcDateString();
  strcnCanlender.innerText = DateString + "\n" + cDateString; //显示!
}
</script>
</head>
<body>
要保存一年的信息,其实只要两个信息就可以了:1.农历每个月的大小?<br/>2.今年是否有闰月.<br/>3.闰几月以及闰月的大小.<br/><br/>用一个整数来保存这些信息就足够了.<br/>具体的方法是:用一位来表示一个月的大?<br/> 笤录俏?,小月记为0,这样就用掉12 位(无闰月)或13 位(有闰月),再用高4位来表示闰月的月份,没有闰月记为0.<br/>比如说,2 0 0 0 年的信息数据是0 x C 9 6 ,化成二进制就是110010010110B,表示的含义是指1、2、5、8、10、11月大,其余月小.<br/>2001 年的农历信息数据是0x41A95,其中4表示今年闰4月,月份大小信息就是0x1A95(因为闰月,所以有13 位),具体的就是1、2、4、5、8、10、12月大,其余月份?<br/>?x1A95=1101010010101B),4月的后面那一个0表示的是闰4月?<br/> 幼诺哪歉?表示5月大.<br/>这样就可以用一个数组来保存这些信息.<br/>在我的JavaScript脚本程序中是用CalendarData[]这个数组来保存这些信息的.<br/>下面就是公历转换成农历的具体算法:1.计算出所求时间到起始年正月初一的天数.<br/>2.从起始年份开始,减去每一月的天数,一直到剩余天数没有下一个月多为止.<br/>此时,CalendarData[]的下标到了多少,就是减去了多少年,用起始年份加上这个下标就可以得到农历年份,然后看减去了几个月.<br/>如果本年不闰月或者闰月还在后面,就可以直接得到农历月份,如果在闰月月份数后面一个月,则这个月就是闰月,如果在闰月的后面,则要减去1 才能得到月份数.<br/>剩余的天数就是农历日,农历时用(公历时+1)/2 就可以简单地得到了.<br/> 
<hr color="#00ff00"/>
<input type="button" value="开始转换" onclick="cnCanlender()"/>
<p id="strcnCanlender" name="strcnCanlender">
</p>
</body>
</html>
Copy after login

The operation rendering is as follows:

PS : Here we recommend several calendar-related online tools for your reference:

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template