新手求助php日历问题
<script> <br /> <br /> function test(){ <br /> var tb = document.getElementsByTagName("table")[0]; <br /> var trs = tb.getElementsByTagName("tr"); <br /> <br /> <br /> <br /> for(var i=0;i<trs.length;i++){ <br /> var td = trs[i].firstChild; <br /> var tdl = trs[i].lastChild; <br /> <br /> td.setAttribute("style","color:red"); <br /> tdl.setAttribute("style","color:red"); <br /> <br /> <br /> } <br /> <br /> var tds = tb.getElementsByTagName("td"); <br /> for(var j=0;j<tds.length;j++){ <br /> <br /> tds[j].onmouseover = function(){ <br /> for(var k=0;k<tds.length;k++){ <br /> tds[k].className=""; <br /> } <br /> this.className="tdborder"; <br /> } <br /> <br /> tds[j].onclick = function(e){ <br /> var div = document.getElementsByTagName("div"); <br /> for(var a=0;a<div.length;a++){ <br /> document.body.removeChild(div[a]); <br /> } <br /> // var w = this.cellIndex; <br /> // alert(w); <br /> var e = e || window.event; <br /> var day = this.innerHTML; <br /> var d = document.createElement("div"); <br /> d.style.border = "1px solid red"; <br /> d.style.position = "absolute"; <br /> d.style.zIndex = 22; <br /> d.style.left = e.clientX+20 + "px"; <br /> d.style.top = e.clientY+5 + "px"; <br /> d.style.width = "100px"; <br /> d.style.height = "100px"; <br /> d.innerHTML = day; <br /> <br /> document.body.appendChild(d); <br /> <br /> } <br /> <br /> } <br /> <br /> <br /> } <br /> <br /> window.onload = test; <br /> <br /> <br /> </script>
$year = 2014;
$month =4;
$total = 0;
$isRN = false;
$month_day = 0;
if($year % 4 == 0 && $year % 100 != 0 || $year % 400 == 0){
$isRN = true;
}
for($i=1900;$i if($i % 4 == 0 && $i % 100 != 0 || $i % 400 == 0){
$total += 366;
}else{
$total += 365;
}
}
for($i=1;$i switch($i){
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
$month_day = 31;
break;
case 2:
if($isRN){
$month_day = 29;
}
else{
$month_day = 28;
}
break;
default:
$month_day = 30;
break;
}
if($i $total += $month_day;
}
}
$temp = $total % 7 + 1;
if($temp == 7){
$temp = 0;
}
echo "
| 星期天 | 星期一 | 星期二 | 星期三 | 星期四 | 星期五 | 星期六 |
|---|---|---|---|---|---|---|
| "; | ".$i." | ";|||||
";
?>
本人想点击日期在div内显示出这是今年的第多少天和星期几。求大神帮帮忙
回复讨论(解决方案)
<?php //设置为中国时区 date_default_timezone_set('PRC'); //打印出今天是星期几（英文的） echo date('l'); //打印出明天是星期几 echo date('l',time()+60*60*24); /* *因为不知道你所设置的时间格式，上面使用的是时间戳 *如果你是2014-7-8这类格式的话，可以使用strtotime()先转换为时间戳 */ echo date('l',strtotime('2014-4-19')); //或者这样 echo date('l',mktime(23,59,59,4,19,2014)); //相信上面说的几个函数应该可以满足你需求了，不行再问，但是自己先去查手册 //获取今天是今年的第几天,其他格式查看上面，是一样的 echo date('z');?>
<html> <head> <title></title> <meta http-equiv="Content-Type" content="text/html;charset=UTF-8"/> <style> .tdborder{ border: 1px solid red; } </style> <script type="text/javascript"> function test(){ var tb = document.getElementsByTagName("table")[0]; var trs = tb.getElementsByTagName("tr"); for(var i=0;i<trs.length;i++){ var td = trs[i].firstChild; var tdl = trs[i].lastChild; td.setAttribute("style","color:red"); tdl.setAttribute("style","color:red"); } var tds = tb.getElementsByTagName("td"); for(var j=0;j<tds.length;j++){ tds[j].onmouseover = function(){ for(var k=0;k<tds.length;k++){ tds[k].className=""; } this.className="tdborder"; } tds[j].onclick = function(e){ var div = document.getElementsByTagName("div"); for(var a=0;a<div.length;a++){ document.body.removeChild(div[a]); }// var w = this.cellIndex;// alert(w); var e = e || window.event; var day = this.innerHTML; var d = document.createElement("div"); d.style.border = "1px solid red"; d.style.position = "absolute"; d.style.zIndex = 22; d.style.left = e.clientX+20 + "px"; d.style.top = e.clientY+5 + "px"; d.style.width = "100px"; d.style.height = "100px"; d.innerHTML = day+" 第几天:"+this.getAttribute('djt')+" 星期几:"+this.getAttribute('xqj');//自己在美化下 星期几：0表示星期日 2表示星期一 document.body.appendChild(d); } } } window.onload = test; </script> </head> <body> <?php $year = 2014; $month =4; $total = 0; $isRN = false; $month_day = 0; if($year % 4 == 0 && $year % 100 != 0 || $year % 400 == 0){ $isRN = true; } for($i=1900;$i<$year;$i++){ if($i % 4 == 0 && $i % 100 != 0 || $i % 400 == 0){ $total += 366; }else{ $total += 365; } } $preTotal = $total;//定义一个今年之前的天数 for($i=1;$i<=$month;$i++){ switch($i){ case 1: case 3: case 5: case 7: case 8: case 10: case 12: $month_day = 31; break; case 2: if($isRN){ $month_day = 29; } else{ $month_day = 28; } break; default: $month_day = 30; break; } if($i < $month){ $total += $month_day; } } $temp = $total % 7 + 1; if($temp == 7){ $temp = 0; } echo "<table>"; echo "<tr><th>星期天 </th> <th>星期一 </th> <th>星期二 </th> <th>星期三 </th> <th>星期四 </th> <th>星期五 </th> <th>星期六 </th></tr>"; for($i=1;$i<=$month_day;$i++){ if($i==1){ echo "<tr>"; } if($temp != 0){ for($j=0;$j<$temp;$j++){ echo "<td></td>"; } $temp = 0; } echo "<td xqj = ".(($total+$i + 1) %7)." djt=".($total+$i - $preTotal).">".$i."</td>";//xqj：表示星期几 如：0=星期日 djt:表示今年的第几天 if(($total+$i + 1) %7 == 0){ echo "</tr><tr>"; } if($i == $month_day){ echo "</tr>"; } } echo "</table><br/>"; ?> </body></html>
感谢大神。谢谢了
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