服务器端如何向客户端发送数据？
我用post方法向服务器端发送了一个用户名和密码，想利用php实现服务器对该行为的响应，返回一个登录成功的字符串，该如何实现呢？客户端又该如何获得这个字符串呢？
回复讨论(解决方案)
去看w3school
写了个demo，输入username=fdipzone,password=123456服务器回返回成功，否则返回失败。
client.html
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html> <head> <meta http-equiv="conent-type" content="text/html; charset=utf-8"> <title> client post</title> <script src="//code.jquery.com/jquery-1.11.0.min.js"></script> </head> <body> <script type="text/javascript"> function fsubmit(){ $.post("server.php", { username: $("#username").val(), password: $("#password").val() },function(ret){ if(ret.success==true){ alert('login success'); }else{ alert('login fail'); } },'json'); } </script> <p>username:<input type="text" id="username"></p> <p>password:<input type="text" id="password"></p> <p><input type="button" value="submit" onclick="fsubmit()"></p> </body></html>server.php
<?php$username = isset($_POST['username'])? $_POST['username'] : '';$password = isset($_POST['password'])? $_POST['password'] : '';$ret = array();if($username=='fdipzone' && $password=='123456'){ $ret['success'] = true;}else{ $ret['success'] = false;}echo json_encode($ret);?>ajax吗？ 先说说你是怎样post到服务器的。
<script type="text/javascript">function submits(){// 实现账户与密码向服务器的发送// 服务器地址中传递的有参数a=1// 从服务器端接收数据num// 对num进行乘以2运算，再将结果发送给服务器端}</script><form id="loginform" action="./login.php?a=1" method="post" >username<input type="text" id="username" name="account">password<input type="password" id="pwd" name="password" ><input type="button" onclick="submits();"></form><?phpif($_POST['a'] == 1){$uName = $_POST['account'];$uPassword = $_POST['password'];// 比较数据库中信息（省略）// 向客户端传递数据num// 获得客户端发送来的运算结果}?>就是为了实现客户端先向服务器发送数据，服务器再向客户端响应数据，最后客户端向服务器端发送对响应数据的运算结果。
总共是三轮数据交换过程，这个该怎么实现呢？
三个过程希望能通过点击一次登录按钮，就实现整个过程。
你就是按了一个按钮后，调用一个方法，然后方法里面再callback其他方法。直到流程走完。
可以这样写。
function fsubmit(){
$.post("server.php", { username: $("#username").val(), password: $("#password").val() },function(ret){
if(ret.success==true){
// 登入成功，这里可以调用第二个方法
doSecondFunc();
}else{
alert('login fail');
}
},'json');
}
function doSecondFunc(){
// do sth
如果还有，可以在这里再调用 thrid function
}
地址中可以加入参数吗，比如“server.php?a=1”，这样可以吗？
地址中可以加入参数吗，比如“server.php?a=1”，这样可以吗？
可以 但是 a 需要使用$_GET['a']来获取
<!DOCTYPE html><html><head> <title></title> <script src="http://code.jquery.com/jquery-latest.js"></script></head><body><script> $(document).ready(function () { $.post('test.php?gettest=1', {"test": "test"}, function (data) { alert(data.get); alert(data.post); }, 'json') })</script></body></html>$array = array( 'get' => $_GET['gettest'], 'post' => $_POST['test'],);echo json_encode($array);
搞了一下午，终于弄明白了，谢谢了
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