求截取PHP指定字符串代码
有下面一段html字符串:
bbbb
cccc
dddd
要想输出下面内容:
dddd
即删除中间两个
前面的内容及
的简易代码,由于还要输出为html,不用数组方式。
回复讨论(解决方案)
$s = '<td align="Center" rowspan="2" width="7%">aaaa<br>bbbb<br>cccc<br>dddd<br></td >';echo preg_replace('/<br>\w+/', '', $s, 2);
<td align="Center" rowspan="2" width="7%">aaaa<br>dddd<br></td >
还有点小问题,单独运行没问题,但上面的表达式实际用到我的字符串时,因为第二段br里含有( ),,最后一段br里含有“-”,截取出来有点问题。
$s = '
11(22)
cccc
dd-dd
截取出来变成了:
$s = '
cccc-dd
$s = '<td align="Center" rowspan="2" width="7%">aaaa<br>11(22)<br>cccc<br>dd-dd<br></td >';echo preg_replace('/<br>[\(\)-\w]+/', '', $s, 2);
补充说明:aaaa、cccc是中文。
补充说明:aaaa、cccc是中文。
$s = '<td align="Center" rowspan="2" width="7%">中文<br>11(22)<br>拼音<br>dd-dd<br></td >';echo preg_replace('/<br>[\x{4e00}-\x{9fa5}\w\(\)-]+/u', '', $s,2) ;//UTF-8编码
谢谢。第一段截取出来的还是错位,还是直接贴我原始的字符吧:
1-9(1,2)
王某
3-307
要想输出两种效果:
1.
3-307
2.
1-9
3-307
1
echo preg_replace('/<br>[^<]+/', '', $s, 2);
2
echo preg_replace('/\(.+?\)/', '', $s);
1
echo preg_replace('/<br>[^<]+/', '', $s, 2);
2
echo preg_replace('/\(.+?\)/', '', $s);
谢谢版主,第一条正确了,第二条的“王某
还在。
echo preg_replace('/<br>[\x{4e00}-\x{9fa5}\w\(\)\-,]+/u', '', $s,2) ;//UTF-8编码
你多了,逗号在【】方括号里面加进去啊
<?php$str = '<td align="Center" rowspan="2" width="7%">aaaa<br>bbbb<br>cccc<br>dddd<br></td >';$arr = explode('<br>', $str);array_splice($arr, 1, 2);echo implode('<br>', $arr);?>
请jordan102帮忙,第二条 echo preg_replace('/\(.+?\)/', '', $s) 还需要截掉“王某
“的部分。
echo preg_replace_callback('/<br>[^<]+/', 'foo', $s, 2); function foo($m){ return strpos($m[0], '(') !== false ? preg_replace('/\(.+?\)/','',$m[0]) : ''; }
谢谢,单独对于一句里面的运行没问题了。但前面还有些语句和空格之类的加上运行就有问题了。

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