php请教

WBOY
Release: 2016-06-23 14:00:18
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$userMsg=$_POST['UserMsg'];  //ajax获取前台传递的对象
$userMsg->userName;//获取对象的属性

不知道 是不是这样写?求解?


回复讨论(解决方案)

print_r($_POST);
看看都有什么?

 Array
(
    [UserMsg] => [object Object]
    [Arr] => [object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
)

是Object

你的 js 代码?

除了 json 其他对象不可以被传递,应该是你哪里搞错了

//获取对象用户的信息
var userMsg=new Object();
userMsg.kecheng=kecheng;
userMsg.company=company;

这个是我传递的js对象


是不是  我把这个对象  json转换下     php后台就能认识呢?

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