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php使用sqlsrv调用sql2008存储过程，如何取得返回值

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Release： 2016-06-23 14:00:19
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代码如下：

存储过程在sql2008里调用时：

就想得到"现在是2014-03-20 09:54:44    "和"你发给服务器的指令是 请假 和客户吃饭呢。 接口尚在开发中。"

求指导


回复讨论(解决方案)

sqlsrv_fetch_array
Copy after login

问题已解决，上网查了好多资料。楼上正解，但还少些细节罢了，感谢！

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php使用sqlsrv调用sql2008存储过程，如何取得返回值
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