php使用sqlsrv调用sql2008存储过程,如何取得返回值
代码如下:
存储过程在sql2008里调用时:
就想得到"现在是2014-03-20 09:54:44 "和"你发给服务器的指令是 请假 和客户吃饭呢。 接口尚在开发中。"
求指导
回复讨论(解决方案)
sqlsrv_fetch_array
问题已解决,上网查了好多资料。楼上正解,但还少些细节罢了,感谢!

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