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Home Backend Development PHP Tutorial php ADO access数据库 update语句无法引用主键的值

php ADO access数据库 update语句无法引用主键的值

Jun 23, 2016 pm 02:01 PM

注意 No 为access表里的主键

我想将No=290的记录里的 ID改为11,下面二句执行后无变化
$query = "update sensors set ID=11 where No=290";
$result =$conn->Execute($query); 
-----------------------------------------------
但下面二句执行后是有效果的,能将type=49的记录ID改为11
$query = "update sensors set ID=11 where type=49";
$result =$conn->Execute($query); 
------------------------------------------------

想知道为什么引用主键的值就不行呢?


回复讨论(解决方案)

这样试试:
update sensors set ID=11 where No=290 and type=49

是不是主键重复了~

这样试试:
update sensors set ID=11 where No=290 and type=49

是不是主键重复了~

主键系统自动增加的,是惟一的,不可能有重复值
我下面这句话是OK的,(XXXXXX是具体的需要更新的字段)
update sensors set XXXXXXXX  where ID=15 and type=48 and prop=0


这样试试:
update sensors set ID=11 where No=290 and type=49

是不是主键重复了~

主键系统自动增加的,是惟一的,不可能有重复值
我下面这句话是OK的,(XXXXXX是具体的需要更新的字段)
update sensors set XXXXXXXX  where ID=15 and type=48 and prop=0


select * from sensors where No=290  看看

帮你转到PHP区了,是不是type字段是字符类型的,换成这样试试

 update sensors set ID=11 where type='49'
Copy after login

no 是 access 的保留字(见  http://office.microsoft.com/zh-cn/access-help/HA010030643.aspx)
在选择标识符名称时应避免使用的保留字
如果已经用了,并且不方便修改的话,应进行转义:用中括号括起

$query = "update sensors set ID=11 where [No]=290";

no 是 access 的保留字(见  http://office.microsoft.com/zh-cn/access-help/HA010030643.aspx)
在选择标识符名称时应避免使用的保留字
如果已经用了,并且不方便修改的话,应进行转义:用中括号括起

$query = "update sensors set ID=11 where [No]=290";

测试了一下,确实如楼上所说No是保留字,将它用方括号包起来就能得到正确的结果了,谢谢,结贴给分!~

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