PHP 类初始化的时候,不能用变量参数么,怎么改呢?
在做 同志湾,然后遇到了问题。
我就想当函数用就够了,直接双引号没问题,换成变量就不响应。额
$entxt=$_GET["entxt"];
echo $entxt;
$x = new fanyi($entxt,1);
echo $x->go();
class fanyi
{
回复讨论(解决方案)
直接双引号没问题,换成变量就不响应。
没理解
直接双引号没问题,换成变量就不响应。
没理解
这个可以:
<?php$entxt=$_GET["entxt"];echo $entxt;$x = new fanyi($entxt;,1);echo $x->go();class fanyi{var $cilentID;var $clientSecret;var $authUrl;var $scopeUrl;var $grantType;var $inputstring;var $toLanguage;var $fromLanguage;function __construct($inputstring,$biao='0'){
这个不行
$entxt=$_GET["entxt"];
echo $entxt;
$x = new fanyi("hello baby",1);
echo $x->go();
class fanyi
{
var $cilentID;
var $clientSecret;
var $authUrl;
var $scopeUrl;
var $grantType;
var $inputstring;
var $toLanguage;
var $fromLanguage;
function __construct($inputstring,$biao='0')
{
直接双引号没问题,换成变量就不响应。
没理解
说反了,上面的不行,下面的可以
new fanyi($entxt ;,1);
多了个分号,造成语法错误不能解析,而你又屏蔽了错误提示,所以没能发现这个问题
同楼上,多了个分号

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