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php 类 疑问

WBOY
Release: 2016-06-23 14:05:56
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文件Db.class.php 定义数据库操作类Db
文件connect.php 实例化数据库:$db=new Db()
文件function.class.php定义其他类
现有 class A{
              function test(){
                     include('connect.php');
                      $db为什么在这里不能使用?
              }
}


回复讨论(解决方案)

那在connect.php 中 $db 可用吗

1、确定 connect.php 文件中的 $db是否可用;
2、确认connect.php的文件路径没有引用错误

文件是否include成功了?

还有一种可能:Db.class.php 被重复加载了

connect.php 贴出来就看看

文件connect.php 实例化数据库:$db=new Db()  这个样例:

class connect()
{
    public $db;

    构造函数: $this->db=new Db()

}


class A{ 

使用:$aa = new  connect;

$aa ->db->....

  }

我觉得版主说的有道理 有可能重载了

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