php已get方式获取参数，处理后如何返回值
a.php从别的地址(b.aspx)接收一个参数（get方式）
a.php处理以后返回一个0到本身页面,例如a.php?0
b.aspx就可以通过getresponse接收到这个返回的0
请问a.php里如何返回一个0给自己？
回复讨论(解决方案)
什么叫返回一个0到本身页面？
$id = $_GET['id'];
echo $id;
输出到本页面还是加在url上?
比如我这个页面就是a.php
b.aspx用get传过来一个参数
a.php接收并处理后，在自己a.php后面加一个参数0：a.php?0
b.aspx用getResponese获取到这个返回的0
我只想知道在b.php里怎么样返回这样一个0
b.aspx用下面语句发送一个get请求参数给a.php，并要获取a.php的返回值
httpRes = HttpWebRequest.Create(new Uri(a.php + strUrlParameter)).GetResponse();
请问在a.php里如何返回值
估计是 ajax 吧？不知是不是与你说的是一回事
估计是 ajax 吧？不知是不是与你说的是一回事
和ajax没有关系
看的不是很懂。
b.aspx用下面语句发送一个get请求参数给a.php，并要获取a.php的返回值
httpRes = HttpWebRequest.Create(new Uri(a.php + strUrlParameter)).GetResponse();
请问在a.php里如何返回值
a.php里echo返回值即可
a.php里echo返回值即可
是要返回给b.aspx的
ajax技术可以实现，直接在a.php中返回一个值可以直接用echo "要返回的值"，这是页面a中echo不是输出信息到浏览器的意思，而是返回值到b的意思,b就可以获取到返回的值了
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