jquery 向 php 传值
怎样将jquery中的值传给当前页面的php中(不刷新页面)?,请给个示例代码。
回复讨论(解决方案)
$.ajax({ url: "test.php", context: document.body, success: function(){
$(this).addClass("done");
}});
$.post("btdz.php", {title : i,action : 1},function(data){
alert(data);
});
})
不刷新是不可能的,局部刷新。
建立两个页面,分别为a.php和b.php
a.php
<?php header('Content-type: text/html; charset=utf-8');?><style>div{display:none}</style><script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script><script type="text/javascript"> $(function(){ $("#abv").click(function(){ var t=$("#a").val(); $.getJSON("b.php",{id:t},function(result){ $("div").hide(); if(result==1){ $("#div1").show(); }else if(result==2){ $("#div2").show(); }else{ alert("密码有误"); return false; } }); }); })</script><input type="text" id="a"/><!--把密码域改成文本域是为了让你看的更直观,如果不习惯,请把type="text"改成type="password"--><input type="button" id="abv" value="测试用按钮"/><div id="div1">下载链接1</div><div id="div2">下载链接2</div>
b.php
<?php $id=$_GET['id']; if($id==123){ echo 1; }else if($id==1234){ echo 2; }else{ echo 3; }?>
我之前给别人写的一个注册页面:http://bbs.csdn.net/topics/390398302,的17楼。
谢谢各位,是我没把问题说清楚,我的意思是根据变量的新值重新刷新页面中的一个局部div中的内容
js dom 操作就可以了
var s='xxxx';
document.getElementById('div').innerHTML=s;
谢谢各位,是我没把问题说清楚,我的意思是根据变量的新值重新刷新页面中的一个局部div中的内容
不明白是什么意思
楼主可能你这个想法的出发点就有问题。
首先PHP是一个服务器端的脚本语言,你拿到的页面是经过PHP服务器解析后的静态HTML页面。
如果想实现无刷新修改页面内容,可以通过ajax异步想PHP发送请求得到数据再用jquery操作dom。
在当前页面向PHP传递jquery的变量值儿不经过服务器的话是不可能的。
谢谢各位,结贴了

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