如何判断数组里面有多少个相同元素?
$a=array('2','1','2');//如何判断里面有几个相同的元素,并且知道相同的元素在什么位置
求指点谢谢
回复讨论(解决方案)
获取相同元素的个数可以使用 array_count_values,这个获取
$a=array('2','1','2');
print_r(array_count_values($a));
?>
得出结果是Array ( [1] => 1 [2] => 2 )
但是要想即只能得到相同个数并想知道下标的,目前想到的就是循环数组然后做比较了
我只写了一个统计相同元素,至于位置的话,去遍历$value!=1的元素就可以了
$array=array("a","b","c","a","c","d","a");function search($ar){ $cnt=count($ar); $br=array(); for($i=0;$i<$cnt;$i++){ $t=$ar[$i]; //echo $t; if(!$br[$t]){ $br[$t]=1; }else{ $br[$t]++; } } return $br;}$cr=search($array);print_r($cr);
Array ( [a] => 3 [b] => 1 [c] => 2 [d] => 1 )
$a = array('2','1','2');$xt = array_diff(array_count_values($a), array(1));print_r($xt);foreach(array_keys($xt) as $v) { echo $v, ': ', join(',', array_keys(array_filter($a, function($c) use ($v) { return $c == $v; })));}
Array
(
[2] => 2
)
2: 0,2
这么晚了,感谢LS几位的帮忙哈,谢谢了

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