


Conversion between Baidu coordinates (BD09), National Bureau of Surveying coordinates (Mars coordinates, GCJ02), and WGS84 coordinate systems_javascript skills
When faced with different coordinate systems in the project, the display on the map will be somewhat deviated. The following is the conversion method written using javascript. The specific code is as follows:
//定义一些常量 var x_PI = 3.14159265358979324 * 3000.0 / 180.0; var PI = 3.1415926535897932384626; var a = 6378245.0; var ee = 0.00669342162296594323; /** * 百度坐标系 (BD-09) 与 火星坐标系 (GCJ-02)的转换 * 即 百度 转 谷歌、高德 * @param bd_lon * @param bd_lat * @returns {*[]} */ function bd09togcj02(bd_lon, bd_lat) { var x_pi = 3.14159265358979324 * 3000.0 / 180.0; var x = bd_lon - 0.0065; var y = bd_lat - 0.006; var z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi); var theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi); var gg_lng = z * Math.cos(theta); var gg_lat = z * Math.sin(theta); return [gg_lng, gg_lat] } /** * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换 * 即谷歌、高德 转 百度 * @param lng * @param lat * @returns {*[]} */ function gcj02tobd09(lng, lat) { var z = Math.sqrt(lng * lng + lat * lat) + 0.00002 * Math.sin(lat * x_PI); var theta = Math.atan2(lat, lng) + 0.000003 * Math.cos(lng * x_PI); var bd_lng = z * Math.cos(theta) + 0.0065; var bd_lat = z * Math.sin(theta) + 0.006; return [bd_lng, bd_lat] } /** * WGS84转GCj02 * @param lng * @param lat * @returns {*[]} */ function wgs84togcj02(lng, lat) { if (out_of_china(lng, lat)) { return [lng, lat] } else { var dlat = transformlat(lng - 105.0, lat - 35.0); var dlng = transformlng(lng - 105.0, lat - 35.0); var radlat = lat / 180.0 * PI; var magic = Math.sin(radlat); magic = 1 - ee * magic * magic; var sqrtmagic = Math.sqrt(magic); dlat = (dlat * 180.0) / ((a * (1 - ee)) / (magic * sqrtmagic) * PI); dlng = (dlng * 180.0) / (a / sqrtmagic * Math.cos(radlat) * PI); var mglat = lat + dlat; var mglng = lng + dlng; return [mglng, mglat] } } /** * GCJ02 转换为 WGS84 * @param lng * @param lat * @returns {*[]} */ function gcj02towgs84(lng, lat) { if (out_of_china(lng, lat)) { return [lng, lat] } else { var dlat = transformlat(lng - 105.0, lat - 35.0); var dlng = transformlng(lng - 105.0, lat - 35.0); var radlat = lat / 180.0 * PI; var magic = Math.sin(radlat); magic = 1 - ee * magic * magic; var sqrtmagic = Math.sqrt(magic); dlat = (dlat * 180.0) / ((a * (1 - ee)) / (magic * sqrtmagic) * PI); dlng = (dlng * 180.0) / (a / sqrtmagic * Math.cos(radlat) * PI); mglat = lat + dlat; mglng = lng + dlng; return [lng * 2 - mglng, lat * 2 - mglat] } } function transformlat(lng, lat) { var ret = -100.0 + 2.0 * lng + 3.0 * lat + 0.2 * lat * lat + 0.1 * lng * lat + 0.2 * Math.sqrt(Math.abs(lng)); ret += (20.0 * Math.sin(6.0 * lng * PI) + 20.0 * Math.sin(2.0 * lng * PI)) * 2.0 / 3.0; ret += (20.0 * Math.sin(lat * PI) + 40.0 * Math.sin(lat / 3.0 * PI)) * 2.0 / 3.0; ret += (160.0 * Math.sin(lat / 12.0 * PI) + 320 * Math.sin(lat * PI / 30.0)) * 2.0 / 3.0; return ret } function transformlng(lng, lat) { var ret = 300.0 + lng + 2.0 * lat + 0.1 * lng * lng + 0.1 * lng * lat + 0.1 * Math.sqrt(Math.abs(lng)); ret += (20.0 * Math.sin(6.0 * lng * PI) + 20.0 * Math.sin(2.0 * lng * PI)) * 2.0 / 3.0; ret += (20.0 * Math.sin(lng * PI) + 40.0 * Math.sin(lng / 3.0 * PI)) * 2.0 / 3.0; ret += (150.0 * Math.sin(lng / 12.0 * PI) + 300.0 * Math.sin(lng / 30.0 * PI)) * 2.0 / 3.0; return ret } /** * 判断是否在国内,不在国内则不做偏移 * @param lng * @param lat * @returns {boolean} */ function out_of_china(lng, lat) { return (lng < 72.004 || lng > 137.8347) || ((lat < 0.8293 || lat > 55.8271) || false); } //使用示例 //gps坐标转火星坐标 var lng_lat_1 = wgs84togcj02(113.912743,22.497629); console.log('火星坐标...',lng_lat_1); //火星坐标转百度坐标 var lng_lat_2 = gcj02tobd09(lng_lat_1[0], lng_lat_1[1]); console.log('百度坐标...',lng_lat_2);

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