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这段代码为什么无法 加入链接啊
Jun 23, 2016 pm 02:14 PM
php href MySQL
<html> <head> <title> New Document </title> </head> <body> <?php$link = mysql_connect( '127.0.0.1', 'root', '520928' ) or die( mysql_error() );//连接数据库服务器 mysql_select_db( 'test' );//选择数据库 mysql_set_charset( 'utf8' );//设置字符编码 $sql = "SELECT * FROM wxtree";//查询分类表 $result = mysql_query( $sql ); $tree = array();//初始化一个数组 while( $row = mysql_fetch_assoc( $result ) ) { $tree[$row['fid']][$row['id']] = $row['cat_name'];//创建分类数组 } mysql_close( $link );//关闭数据库 print_r($tree[02]);echo '-------------------------------------------' . "\n"; //递归函数 function for_category( $arr = array(), $arr2 ){ echo "<ul>"; foreach ( $arr as $k => $v ) { if ( isset( $arr2[$k] ) && is_array( $arr2[$k] ) ) { echo "<li>$k $v<td>         <td><a href="http://www.w3school.com.cn">W3School</a> 添加</td><td> 编辑 </td><td> 删除 </td>" ; for_category( $arr2[$k], $arr2 ); echo "</li>"; } else{ echo "<li>$k $v<td>         <td><a href="http://www.w3school.com.cn">W3School</a> 添加</td><td> 编辑 </td><td> 删除 </td> </li>" ; } } echo "</ul>"; } for_category( $tree[0], $tree );?><a href="http://www.w3school.com.cn">W3School</a> </body></html>//链接正确,这里 echo "<li>$k $v<td>         <td><a href="http://www.w3school.com.cn">W3School</a> 添加</td><td> 编辑 </td><td> 删除 </td>" ; 加入链接,为什么报错
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回复讨论(解决方案)
报错的原因是双引号中的双引号没有转义
但修改后依然不会达到你的目的
因为 td 标记不予许单独出现在 li 标记中
那怎么办,还需要加
tr、td 只能出现在 table 中
加入table之后,就没有之前的效果了,
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