php操作数组

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Release: 2016-06-23 14:15:20
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for($i=1;$i<=5;$i++){	array(array($i));}
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for循环里面的是一个二维数组,我想把for循环里面的二维数组进行合并,打印出来的结果是:

array( [0] => Array        (      [0] => 1     ) [1] => Array        (      [0] => 2       ) [2] => Array        (      [0] => 3      ) [3] => Array        (      [0] => 4  ) [4] => Array        (       [0] => 5       ))
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回复讨论(解决方案)

$rs = array();for($i=0; $i<=5; $i++) {    $rs[] = array($i);}
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$rs = array();for($i=0; $i<=5; $i++) {    $rs[] = array($i);}
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这个方法不行,右边的array(array($i));你是不能拆的,必须是一个二维数组。


$rs = array();for($i=0; $i<=5; $i++) {    $rs[] = array($i);}
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这个方法不行,右边的array(array($i));你是不能拆的,必须是一个二维数组。
你有没把我的代码运行,看结果没?

我知道这个结果是正确的,但是你不能这样操作

$rs[] = array($i);
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右边必须得是:
array(array($i))
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$rs = array();for($i=0; $i<=5; $i++) {    $tmp = array(array($i));//这样行吗?    $rs[] = $tmp[0];}
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$rs = array();for($i=0; $i<=5; $i++) {    $tmp = array(array($i));//这样行吗?    $rs[] = $tmp[0];}
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此方法,不行,你只能得到$i的数字,如果二维数组里面还有其它的元素就无法获取了。

for($i=1;$i<=5;$i++){  $res[$i] = array(array($i));}
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for($i=1;$i<=5;$i++){  $res[$i] = array(array($i));}
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得到的已经是三维的数组,要的结果是二维数组。

$res = array();for($i=1;$i<=5;$i++){  $res = array_merge($res, array(array($i)));}print_r($res);
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Array
(
    [0] => Array
        (
            [0] => 1
        )

    [1] => Array
        (
            [0] => 2
        )

    [2] => Array
        (
            [0] => 3
        )

    [3] => Array
        (
            [0] => 4
        )

    [4] => Array
        (
            [0] => 5
        )

)

OK,正解,谢谢老大。

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