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Home Backend Development PHP Tutorial 每天更新一次,以三天为一个周期调取不同分类,求指教

每天更新一次,以三天为一个周期调取不同分类,求指教

Jun 23, 2016 pm 02:16 PM

本帖最后由 AspDelphi 于 2013-07-18 11:34:01 编辑

导入规则:每3天为一个周期依次调取以下分类中日点击量最高的10组图集,每天更新一次
调取分类:
    时装  奢华  人物  生活  街拍
    美容  婚嫁  明星  测试  图库

    化妆品  试用  品牌
    导购
下的图集

回复讨论(解决方案)

没看明白哪里有难点,   每天一次定时去数据库里分别取就是了 三天内的记录中筛选.

如果是时间问题,有很多种方案,比如你设定一个起始日期,拿现有的日期去和它对比就得到现有的日期在哪一个三天的周期内,然后between and 查询就是了

$s = strtotime('2013-06-15 00:00:00');
$e = time();
$arr = array(
'100,2113',//时装    3    
'100,2114',//奢华、  6
'100,2115',//人物、9
'103,2124',//生活、 12
'102,2120',//街拍、15
'100,2122',//美容、 18
'100,2123',//明星 、
'104,2127',//测试、
'104,2128',//图库、
'104,2128,3770',//化妆品、
'104,2142',//试用、
'105,2130',//品牌、
'105,2137',//秀场、
'100,2112',//导购
);  //42
$days = floor(($e-$s)/(24*60*60));//取得今天到我第一次程序执行时的天数
$key =  floor($days/3);//当超过42天$key值就不对了
这个$key的获取要怎么写才好呢

$arr[$key] 这就是我当天要取得的分类

就是说你程序都已经OK了只是当超过42天就出问题了对吧?

那在你
$days = floor(($e-$s)/(24*60*60));//取得今天到我第一次程序执行时的天数
$key =  floor($days/3);//当超过42天$key值就不对了
之间加一个
$days = fmod($days,count($arr)*3);

$days = floor(($e-$s)/(24*60*60));//取得今天到我第一次程序执行时的天数$days = fmod($days,count($arr)*3);//$days总是小于一轮循环的天数$key =  floor($days/3);//当超过42天$key值就不对了
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