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Home Backend Development PHP Tutorial each() 返回4个值, list 赋值哪两个

each() 返回4个值, list 赋值哪两个

Jun 23, 2016 pm 02:16 PM

each list

初学php,请问each() 返回4个值, list 赋值哪两个
$prices = array('Tires' => 100, 'oil' => 10, 'Spark Plugs' => 4);
$item = each($prices);
print_r($item);
echo "
";
reset($prices);
while(list($a, $b) = each($prices)) {
echo "a:$a,b:$b 
";
}
?>
each($prices)的值是4个key value 的数组,
Array ( [1] => 100 [value] => 100 [0] => Tires [key] => Tires ) 

而list($a, $b) = each($prices)) 为什么会把$item[key],$item[value]赋值给$a, $b,而不是$item[1],$item[value]。
list不应该是顺序赋值么。
网上找了,官方文档文档也找了,都没有准确答案,各位同学求解额

回复讨论(解决方案)

有两个可能你没看到
 1.
   list() only works on numerical arrays and assumes the numerical indices start at 0.
也就是,优先使用的是数字索引的值。 
2.
list() assigns the values starting with the right-most parameter.
从参数列表的最右边开始赋值,所以$b 被赋值 0索引的值,也就是Tires ,然后$a被赋值1索引的值,所以是100

观察如下事实:

list($a, $b) = array('a', 'b');echo "a:$a b:$b\n"; //输出 a:a b:blist($a, $b) = array(1 => 'a', 0 => 'b');echo "a:$a b:$b\n"; //输出 a:b b:alist($a, $b) = array('a'=>'a', 'b'=>'b');echo "a:$a b:$b\n"; //输出 a: b:错误信息: Undefined offset: 1  Undefined offset: 0 
Copy after login

可知 list 是按参数列表的序号依次从数组中提取相应的下标元素的
即列表中的变量的值就是数组下标的值,而与数组中下标的排列次序无关

那么特别的指出“从参数列表的最右边开始赋值”的意义何在呢?
请看这样的写法
list($a[$b][$c], $b, $c) = array('a', 'b', 'c');print_r($a);
Copy after login
Array
(
    [b] => Array
        (
            [c] => a
        )
)
由于 $c、$b 先于 $a 赋值,所以在向 $a[$b][$c] 赋值的时候不会出错

感谢上面两位同学,
主要是这句话确实看掉了,
list() only works on numerical arrays and assumes the numerical indices start at 0. 
list() 只工作于 索引从 0 开始的 数值数组 

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