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PHP 日期格式转换去除问题

WBOY
Release: 2016-06-23 14:20:35
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php

界面传到PHP里面
2013-01-01 12:01:00
$endtime   = $this->input->get('endtime');
$endtime  = preg_replace('/[- :]/','',$endtime ); 
现在的格式
20130101120100

想实现的格式是
20130101000000
把时分秒替换为0 怎么实现? 大虾帮忙! 

回复讨论(解决方案)

$s = '2013-01-01 12:01:00';
$s = date('Ymd000000', strtotime($s));

思路问题 

既然格式是这样的 那其实就是 字符串的前8个数字+6个0

echo substr($endtime,0,8)."000000";

好吧 xu大的方法更合适的多...

$s = '2013-01-01 12:01:00';
$s = date('Ymd000000', strtotime($s));

版主爱你一万年 

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