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Home Backend Development PHP Tutorial 【紧急求助】Fatal error: Call to a member function *** on a non-object

【紧急求助】Fatal error: Call to a member function *** on a non-object

Jun 23, 2016 pm 02:21 PM

本帖最后由 keric2008 于 2013-08-26 18:33:02 编辑

php class

源代码很长,抽象下,大概流程是这样的。

{
    $instest = new test();
    $insobject = new object();
    $instest->test();
}

class test{
    function test(){
        $insobject->hello();
    }
}

class object{
    function hello(){
        echo "hello";
    }
}
这样就会出现 如题的错误:Fatal error: Call to a member function hello() on a non-object in /home/latelx64/workspace/zhebo/init.php on line 158

难道是在实例里不能调用其他实例的public函数么?

如果不能的话应该如何以类似的方式解决呢???
本人新学PHP,希望各位高手给予指导!!!

回复讨论(解决方案)

如果你非要这样做的话,那么函数就需要传参,传一个对象进来。

{$instest = new test();$insobject = new object();$instest->test($insobject);}class test{function test($insobject){$insobject->hello();}}class object{function hello(){echo "hello";}}
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Copy after login


一般从设计的角度来说,采用继承的方式,会更好。

可以用继承举个例子么,非常感谢

源代码很长,抽象下,大概流程是这样的。

{
$instest = new test();
$insobject = new object();
$instest->test();
}

class test{
function test(){
$insobject->hello();
}
}

class object{
function hello(){
echo "hello";
}
}
这样就会出现 如题的错误:Fatal error: Call to a member function hello() on a non-object in /home/latelx64/workspace/zhebo/init.php on line 158

难道是在实例里不能调用其他实例的public函数么?

如果不能的话应该如何以类似的方式解决呢???
本人新学PHP,希望各位高手给予指导!!!

用继承的话,使用父类申明的实例里面的数据,又不会存在于使用子类申明的实例。

这与面向对象无关!
只是个变量作用域的问题!
class test{
function test(){
$insobject->hello();
}
}
中 $insobject 是局部变量,并且也没有赋值。
当然也就没有 hello 方法了

要在每个函数里申明 全局变量么?

这与面向对象无关!
只是个变量作用域的问题!
class test{
function test(){
$insobject->hello();
}
}
中 $insobject 是局部变量,并且也没有赋值。
当然也就没有 hello 方法了

class test{
function test(){
global $insobject;
$insobject->hello();
}
}
这样每个函数里 都要申明不是很复杂么!!没有什么委婉一点的么


这与面向对象无关!
只是个变量作用域的问题!
class test{
function test(){
$insobject->hello();
}
}
中 $insobject 是局部变量,并且也没有赋值。
当然也就没有 hello 方法了

$_ENV['?量名']

?玩意可以超全局使用,?似的?有:

$_GLOBALS['?量名'];$_GET['?量名'];$_POST['?量名'];$_REQUEST['?量名']等

如果你非要这样做的话,那么函数就需要传参,传一个对象进来。

{$instest = new test();$insobject = new object();$instest->test($insobject);}class test{function test($insobject){$insobject->hello();}}class object{function hello(){echo "hello";}}
Copy after login
Copy after login


一般从设计的角度来说,采用继承的方式,会更好。


用你这方法不行。Warning: Missing argument 1 for test::test(), called in C:\wamp\www\zhebo\index.php on line 24 and defined in C:\wamp\www\zhebo\x\init.php on line 170

class test{    function test(){        object::hello();    }}class object{    Public static function hello(){        echo "hello";    }}
Copy after login

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