求一个 sql 拼接的问题 ??
sql 拼接问题 ?
需求:根据省份,客户名称,通气时间这3个条件去排序,可以只选择一个,也可多个,这3个排序条件都是复选框,sql 如下:
$MYSQL->query("select * from customer cu " .$where);
排序条件:
省份
客户名称
通气时间
在 sql 后面拼接的排序条件
if($sel_key10){
$where=$where." order by cu.province "; // 省
}
if($sel_key11){
$where .= " ,cu.KFName"; // 客户名称
}
if($sel_key12){
$where .= " ,cu.GiveGasTime "; // 通气时间
}
我这样拼接的是有问题的,如果 单独以省作为排序条件是没有问题的,但是我单独以其他的作为条件,就不对了,如果我同时以2个,或3个,按照,省,客户名称,通气时间,这样的顺序也是对的,
其实我要的sql 就是 :
select * from customer cu where 1=1 order by cu.province,cu.KFName,cu.GiveGasTime ,如果没有条件就不要 order by ,有就在 括号里面追加。。
排序条件:省份 客户名称 通气时间
回复讨论(解决方案)
可以这么写
$where = array();if($sel_key10){$where[] =" cu.province "; // 省}if($sel_key11){$where[] =" cu.KFName"; // 客户名称}if($sel_key12){$where[] = " cu.GiveGasTime "; // 通气时间 }$MYSQL->query("select * from customer cu " . (!empty($where) ? 'order by '. implode(',',$where) : '');
测试代码
<form method=post><input type="checkbox" name="sel_key10" />省份<input type="checkbox" name="sel_key11" />客户名称<input type="checkbox" name="sel_key12" />通气时间<input type=submit></form><?php$dict = array( 'sel_key10' => 'cu.province', // 省 'sel_key11' => 'cu.KFName', // 客户名称 'sel_key12' => 'cu.GiveGasTime', // 通气时间 );$sql = "select * from customer cu ";if($_POST) { $t = array_intersect_key($dict, $_POST); if($t) $sql .= 'order by ' . join(', ', $t);}echo $sql;
如果改造一下表单,处理起来更简单
<form method=post><input type="checkbox" name="o[]" value="cu.province" />省份<input type="checkbox" name="o[]" value="cu.KFName" />客户名称<input type="checkbox" name="o[]" value="cu.GiveGasTime" />通气时间<input type=submit></form><?php$sql = "select * from customer cu ";if(isset($_POST['o'])) { $sql .= 'order by ' . join(', ', $_POST['o']);}echo $sql;
如果改造一下表单,处理起来更简单
<form method=post><input type="checkbox" name="o[]" value="cu.province" />省份<input type="checkbox" name="o[]" value="cu.KFName" />客户名称<input type="checkbox" name="o[]" value="cu.GiveGasTime" />通气时间<input type=submit></form><?php$sql = "select * from customer cu ";if(isset($_POST['o'])) { $sql .= 'order by ' . join(', ', $_POST['o']);}echo $sql;
容易产生sql注入漏洞, 慎用
#1 ,#2 ,的方法都没成功, #3 版主的方法成功了。谢谢。

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