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新人学习PHP问题,发现书上代码不对

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Release: 2016-06-23 14:25:14
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PHP 基础 继承

在书上发现一段代码,敲下来后发现不对。。
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><?php	class Person	{		private $name;		private $sex;		private $age;				function __construct($name="",$sex="男",$age=23)		{			$this->name=$name;			$this->sex=$sex;			$this->age=$age;		}		function say()		{			echo "我的名字  ".$this->name.",性别  ".$this->sex.",年龄  ".$this->age."<br>";		}		function run()		{			echo $this->name."正在走路<br>";		}	}	class Student extends Person 	{		var $school;		function study()		{			echo $this->name."正在".$this->school."学习<br>";		}	}	class Teacher extends Student 	{		var $wage;		function teaching()		{			echo  $this->sex."正在".$this->school."教学,每个月工资为".$this->wage."<br>";		}	}	$teacher1=new Teacher("张三","男",40);	$teacher1->school="沈阳工学院";	$teacher1->wage=3000;		$teacher1->say();	$teacher1->run();	$teacher1->teaching();?>
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这里Teacher类中的teaching方法或不去不到$this->name。。书上却写可以获取的到,是我哪里写错了吗?

回复讨论(解决方案)

是$this->sex获取不到数据。

额。。。。我马虎了,上面变量定义的是private属性,当然获取不到。。。

同样菜的鸟飞过.........

你没错,书上也没错!
只不过是错误检查的级别不同而已

error_reporting = E_ALL ^ E_NOTICE
就一致了

你没错,书上也没错!
只不过是错误检查的级别不同而已

error_reporting = E_ALL ^ E_NOTICE
就一致了 版主强大,耳目一新,不明觉厉,加油奋进!

 private $name;
 private $sex;
 private $age;
private改成public

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