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Home Backend Development PHP Tutorial 【求大神】访问任意文件url返回任意文件名给用户下载??????

【求大神】访问任意文件url返回任意文件名给用户下载??????

Jun 23, 2016 pm 02:25 PM

访问任意文件url返回任意文件名给用户下载??????

案例:

http://down1.020pidai.com/8935/服务器里面其实只有一个文件..

如000000.exe

要现实的功能是:
用户访问任意名称就可以下载任意名称的文件 , 而不会出现404错位文件不存在的情况

访问
http://down1.020pidai.com/8935/111111.exe
服务器返回111111.exe给用户下载,用户下载看到的文件名为111111.exe而不是服务器上的000000.exe


http://down1.020pidai.com/8935/222222.exe
服务器返回222222.exe给用户下载,,用户下载看到的文件名为222222.exe而不是服务器上的000000.exe


麻烦大神


回复讨论(解决方案)

就是不管用户输什么名字,都只下载000000.exe这个文件?

header("Content-Disposition: attachment; filename=000000.exe");

就是不管用户输什么名字,都只下载000000.exe这个文件?

header("Content-Disposition: attachment; filename=000000.exe");

你的代码是访问任何url下载000000.exe 但接收的文件名是000000.exe

就是不管用户输什么名字,都只下载000000.exe这个文件?

header("Content-Disposition: attachment; filename=000000.exe");

我要的效果是 服务器只有000000.exe 一个文件

用户访问 www.url.com/down/111111.exe 会保存111111.exe而不是保存000000.exe

用户访问 www.url.com/down/222222.exe 会保存222222.exe而不是保存000000.exe

用 urlrewrite 隐去入口文件名
于是 http://down1.020pidai.com/8935/222222.exe 中的 /8935/222222.exe 就作为 PATH_INFO 传入入口文件
而 /8935/222222.exe 中的
8935 就可代表实际的 000000.exe
222222.exe 就是 header("Content-Disposition: attachment; filename=$filename"); $filename

能够理解吗?

用 urlrewrite 隐去入口文件名
于是 http://down1.020pidai.com/8935/222222.exe 中的 /8935/222222.exe 就作为 PATH_INFO 传入入口文件
而 /8935/222222.exe 中的
8935 就可代表实际的 000000.exe
222222.exe 就是 header("Content-Disposition: attachment; filename=$filename"); $filename

能够理解吗?

代码这样写???貌似代码没提及到去下载000000.exe
header("Content-Disposition: attachment; filename=$filename"); $filename
?>

还有怎么访问这个呢?  以上代码保存为exe.php放在根目录www.url.com/exe.php

www.url.com/down/*** 

伪静态重写www.url.com/exe.php  ???

是否这样??

已明白!!

全部代码

新建exe.php
代码:
header("Content-Disposition: attachment; filename=$filename"); $filename
?>

新建.htaccess文件 
代码:
RewriteEngine On
RewriteBase /
RewriteRule ^index\.php$ ? [L]
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . /index.php [L]


新建目录8935
目录8935下新建.htaccess文件 
代码如下:
RewriteEngine On
RewriteBase /8935/
RewriteRule ^000000\.exe$ ? [L]
RewriteRule . /000000.exe [L]


在目录8935下放000000.exe即可

这样就达到访问www.url.com/8935/随意写名字.exe
得到的文件为:
随意写名字.exe

apache可以了iis的httpd.ini 怎么弄呢,可以实现不

用 urlrewrite 隐去入口文件名
于是 http://down1.020pidai.com/8935/222222.exe 中的 /8935/222222.exe 就作为 PATH_INFO 传入入口文件
而 /8935/222222.exe 中的
8935 就可代表实际的 000000.exe
222222.exe 就是 header("Content-Disposition: attachment; filename=$filename"); $filename

能够理解吗?

版主iis可以实现这样的效果吗,httpd.ini里面

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