php字符串操作问题
字符串：{user:link islocal='1'} /2013/userup/100/131a2Z34-5N8.doc {/user:link}
如何取出131a2Z34-5N8字符串？？？
比如有很多类似的字符串：
字符串1：{user:link islocal='1'} /2013/userup/100/131a2Z34-800.doc {/user:link}
字符串2：{user:link islocal='1'} /2013/userup/100/131a2Z34-801.doc {/user:link}
字符串3：{user:link islocal='1'} /2013/userup/100/131a2Z34-802.doc {/user:link}
分别取出字符串：
131a2Z34-800
131a2Z34-801
131a2Z34-802
要用正则吗，如何实现？
回复讨论(解决方案)
$s=<<<txt字符串1：{user:link islocal='1'} /2013/userup/100/131a2Z34-800.doc {/user:link}字符串2：{user:link islocal='1'} /2013/userup/100/131a2Z34-801.doc {/user:link}字符串3：{user:link islocal='1'} /2013/userup/100/131a2Z34-802.doc {/user:link}txt;preg_match_all('#/([^/]+)\.doc\s*{/user#sU',$s,$m);print_r($m[1]); 有这种情况：
{user:link islocal='1'} /我是随机字符串/我是随机字符串/我是随机字符串/我是随机字符串 {/user:link}
只有" {/user:link}"相同，后面不一定是doc，可能是.xls .txt 但一定有.
我想只能从/131a2Z34-802.doc {/user:link}又手，但想不出来
preg_match_all('#/([^/]+?)\.#',$s,$m);print_r($m[1]);
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