Codeforces Round #277.5 (Div. 2)-C_html/css_WEB-ITnose

简单细节题：

#include<iostream>#include<cstdio>#include<cmath>#include<map>#include<cstring>#include<algorithm>#define rep(i,a,b) for(int i=(a);i<(b);i++)#define rev(i,a,b) for(int i=(a);i>=(b);i--)#define clr(a,x) memset(a,x,sizeof a)typedef long long LL;using namespace std;const int mod=1e9 +7;const int maxn=105;const int maxm=905;int da[maxn],db[maxn];int main(){    int n,m;    while(~scanf("%d%d",&n,&m))    {        if(m>9*n||(n!=1&&m==0))        {            printf("-1 -1\n");            continue;        }        int cnt=0,ccnt=0,num=m;        while(num-9>=0)db[ccnt++]=9,num-=9;        if(num)db[ccnt++]=num;        while(n!=ccnt)db[ccnt++]=0;        num=m;        while(1<=num-9)da[cnt++]=9,num-=9;        if(n-1==cnt)        {            da[cnt++]=num;            for(int i=cnt-1;i>=0;i--)                printf("%d",da[i]);            printf(" ");            for(int i=0;i<ccnt;i++)                printf("%d",db[i]);            printf("\n");            continue;        }        da[cnt++]=num-1;num=1;        while(n-1!=cnt)            da[cnt++]=0;        da[cnt++]=1;        for(int i=cnt-1;i>=0;i--)            printf("%d",da[i]);        printf(" ");        for(int i=0;i<ccnt;i++)            printf("%d",db[i]);        printf("\n");    }    return 0;}

C. Given Length and Sum of Digits...

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the decimal base without leading zeroes.

Input

The single line of the input contains a pair of integers m, s (1?≤?m?≤?100,?0?≤?s?≤?900) ? the length and the sum of the digits of the required numbers.

Output

In the output print the pair of the required non-negative integer numbers ? first the minimum possible number, then ? the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).

Sample test(s)

input

2 15

output

69 96

input

3 0

output

-1 -1