Why does this statement always report an error? What went wrong? _html/css

Why does this statement always report an error? What went wrong? _html/css_WEB-ITnose

WBOY

Release： 2016-06-24 12:07:05

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onmouseover='mouseover()‘; Thanks for watching

Are you going to have a good time?

<html><head>    <script type="text/javascript">        function mouseOver(id, pic)        {            document.getElementById(id).src = pic        }        function mouseOut(id, pic)        {            document.getElementById(id).src = pic        }    </script></head><body>    <a target="_blank" href="mailto:support@xxxxxxxx.com">        <img border="0" id="img1" src="e1.png" height="32" width="32" alt="" onmouseover='mouseOver("img1", "e1.png")'onmouseout='mouseOut("img1", "e0.png")'></a>        <a target="_blank" href="https://twitter.com/xxxxxxxx">            <img border="0" id="img2" src="t0.png" height="32" width="32" alt="" onmouseover='mouseOver("img2", "t1.png") 'onmouseout='mouseOut("img2", "t0.png")'></a></body></html>

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Thanks for watching, I'm not sure what to do with it.

What a snowball fight? A snowball fight!

Do you want to make a name for yourself

onmouseover= 'mouseOver("img1", "e1.png") '
onmouseover("img1", "e1.png") '

Thanks for watching Happy birthday?

Happy birthday!!

Thank you, please.

Do you want to have a smile on your face?

Unfortunately?

Thank you!! If you want to take a look at the rest

, you can get the best results Thank you?

Have a nice smile on your face Happy Birthday to you

Happy birthday, please!

Thank you Please feel free to ask me, please contact me.

Thanksgiving