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PHP calculation of days difference between dates example analysis_php skills

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Release: 2016-05-16 19:58:07
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This article analyzes the method of calculating the number of days between dates in PHP. Share it with everyone for your reference, the details are as follows:

<&#63;PHP
//今天与2016年10月27日相差多少天
$Date_1=date("Y-m-d");
$Date_2="2016-10-27";
$d1=strtotime($Date_1);
$d2=strtotime($Date_2);
$Days=round(($d1-$d2)/3600/24);
echo  "今天与2016年10月27日相差".$Days."天";
echo "<br>";
//今天到2018年9月9日还有多少天
$Date_1=date("Y-m-d");
$Date_2="2018-09-09";
$d1=strtotime($Date_1);
$d2=strtotime($Date_2);
$Days=round(($d2-$d1)/3600/24);
echo  "今天到2018年9月9日还有".$Days."天";
&#63;>

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//---------------------------------------------
$arrayStartDate =explode("/",$myStartDate); 
$arrayEndDate = explode("/",$myEndDate);
$jdStartDate = cal_to_jd(CAL_GREGORIAN,$arrayStartDate[1],$arrayStartDate[0],$arrayStartDate[2]);
$jdEndDate = cal_to_jd(CAL_GREGORIAN,$arrayEndDate[1],$arrayEndDate[0],$arrayEndDate[2]);
$duration = $jdEndDate - $jdStartDate + 1;

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Stats data that will expire in a few days

datediff(yxdate_star,now())

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Return the number of days: yxdate_star-now()

Readers who are interested in more PHP-related content can check out the special topics of this site: "PHP Object-Oriented Programming Introductory Tutorial", "Summary of PHP String Usage ", "php mysql database operation introductory tutorial" and "php common database operation skills summary"

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