Home > php教程 > php手册 > body text

PHP method to determine whether json object exists

WBOY
Release: 2016-07-06 13:28:13
Original
906 people have browsed it

In the actual test, when PHP reads the json array and uses simple if or array_key_exists to determine whether the object exists, an error will be reported. The following is the correct judgment method from Google search

In fact, the error is reported because I am not very proficient in PHP, so maybe the correct judgment method I think is not the most perfect solution or even wrong. This blog post is reserved for my own use

Error code:

<span style="color: #800080;">$structure</span> = <span style="color: #008080;">imap_fetchstructure</span>(<span style="color: #800080;">$connection</span>, <span style="color: #800080;">$id</span>,<span style="color: #000000;"> FT_UID);
</span><span style="color: #0000ff;">if</span> (<span style="color: #008080;">array_key_exists</span>('parts', <span style="color: #800080;">$structure</span><span style="color: #000000;">))
{
}</span>
Copy after login

An error message Warning: array_key_exists() expects parameter 2 to be array, boolean given

The correct solution is:

<span style="color: #0000ff;">if</span> (<span style="color: #008080;">is_array</span>(<span style="color: #800080;">$structure</span>) && <span style="color: #008080;">array_key_exists</span>('parts', <span style="color: #800080;">$structure</span>)) <br>{ <span style="color: #008000;">//</span><span style="color: #008000;">...magic stuff here <br>}</span>
Copy after login

Another way is to use isset to judge directly:

<span style="color: #0000ff;">if</span>(<span style="color: #0000ff;">isset</span>(<span style="color: #800080;">$structure</span>['parts'<span style="color: #000000;">]))
 {
 }<br></span>
Copy after login

  //This function is used to test whether the variable has been configured. Returns true if the variable already exists. Otherwise a false value is returned.

// Therefore, it is necessary to return TURE

if the variable exists and the value is not NULL.
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Recommendations
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template