


Implementation method of directory structure for Python to extract Linux kernel source code
Today I used Python to extract the directory tree structure of the Linux kernel source code. I have never written a script program. I actually spent 2 hours on how to enumerate all the files and folders in a given directory, os. Walk can enumerate, but os.walk only gives directory names and file names, but no absolute paths. This can be achieved by using os.path.listdir, and then creating the directory. Since when the directory exists, a creation failure error will be prompted, so I first wanted to delete all directories and then create them again, but I found that there was still a problem. It is best to use Determine if the directory does not exist before creating it. If it exists, do not create it. Paste the code:
# @This script can be used to iterate the given directory,and create the # empty directory structure without file in it,e.g,I want to have you directory # as the linux kernel source, but i don't want the files, then this script comes. # @This script is running under python 3.1 # @author:zhangchao # @Time:2011年7月25日18:43:26 ########################################################################### import os import re #listmydirs is created to recursivly list all the entrys in the specified path. #In fact, we have os.walk to handle this problem # #level:目录的层数,不要也可以,主要是为了显示目录在那一层 #srcpath:内核源代码所在的路路径 #destpath:将要生成的内核源代码的目录结构所在路径 # def createkerneldirs(level,srcpath,destpath): for entrys in os.listdir(srcpath): #学习listdir函数的用法 tmpsrcpath=srcpath+os.sep+entrys tmpdestpath = tmpsrcpath.replace(srcpath,destpath)#将源路径中的E:\linux-2.6替换为E:\tmp,学习字符串替换函数的用法 print('in level:'+str(level)) print(tmpsrcpath) print(tmpdestpath) if os.path.isdir(tmpsrcpath): listmydirs(level+1,tmpsrcpath,tmpdestpath) if os.path.exists(tmpdestpath)==False: #如果文件不存在才创建文件 os.makedirs(tmpdestpath) if __name__=='__main__': #将E:\linux-2.6的内核源代码目录结构拷贝到E:\tmp目录下 createkerneldirs(1,r'E:\linux-2.6',r'E:\tmp')
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