How to debug php after ajax submission?

I recently discovered a problem when I was working on a thinkphp website, that is, after ajax post/get was sent to the php background method, it could not be debugged - -!

Then I searched on the Internet and found that ajax --> php really has no good way to debug... ( This is the key point I want to ask, how to debug php after ajax is submitted? For example, I Want to see the value of a variable in php )

Please help

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I recently discovered a problem when I was working on a thinkphp website, that is, after ajax post/get was sent to the php background method, it could not be debugged - -!

Then I searched on the Internet and found that ajax --> php really has no good way to debug... ( This is the key point I want to ask, how to debug php after ajax is submitted? For example, I Want to see the value of a variable in php )

Please help

Google developer tools, XHR in the network can see the ajax request address, which contains submitted data and background return information

xdebuger

Just Google F12. If you want to see what requests are there, you don’t have to worry about using the debugging tools that come with the framework

chrome ->F12 check->NetWork->XHR

F12 Review Elements

You can write the variables into the file, and then view the file after ajax is executed. If you have tp, you can directly use the log record

Add an xdebug extension and cooperate with the IDE to realize PHP breakpoints and so on.
Then next breakpoint, you can come over and break it as soon as you ask, and you can debug PHP naturally! !

Isn’t Firefox’s firebug pretty good?

file_put_contents('/log.txt',var_export($_POST,true));
//The execution of the program will not be terminated, and the $_POST obtained each time will be output to the log.txt file in the current directory Medium