Is the number of intersections in the two arrays equal?

Count whether the number of intersections in the two arrays is equal. Thank you

====================================
Supplement:
$a= array('1','2');
$b=array('1','2','3','2');

In array a, 1 and 2 appear once each
, but in array b, 1 appears once and 2 appears twice

The intersection is 1 and 2. Now I want to know whether the number of occurrences is equal

Reply content:

Count whether the number of intersections in the two arrays is equal. Thank you

====================================
Supplement:
$a= array('1','2');
$b=array('1','2','3','2');

In array a, 1 and 2 appear once each
, but in array b, 1 appears once and 2 appears twice

The intersection is 1 and 2. Now I want to know whether the number of occurrences is equal

Since it is an intersection, it should be equal. The elements that both arrays have are called intersections. You don’t understand the concept of sets. Sets do not allow duplicate elements.

The basic concept of sets is misunderstood. The elements in a set are mutually exclusive, so they will only appear once. Correspondingly, the intersection elements will only appear once in each set.

Depending on the needs of your example, just traverse the calculated intersection to make a judgment.

<code>$arr1 = [1,2];
$arr2 = [1,2,3,2];

$intersect = array_intersect($arr1, $arr2);

$result = array();
foreach ($intersect as $item) {
    $result[$item] = array('arr1' => 0, 'arr2' => 0);
}

foreach ($arr1 as $item) {
    if (isset($result[$item])) {
        $result[$item]['arr1'] += 1;
    }
}

foreach ($arr2 as $item) {
    if (isset($result[$item])) {
        $result[$item]['arr2'] += 1;
    }
}</code>