


Using BigMap instances in PHP, using BigMap instances in PHP_PHP tutorial
BigMap instances are used in PHP, PHP uses BigMap instances
<?php //所谓的Bit-map就是用一个bit位来标记某个元素对应的Value, 而Key即是该元素。由于采用了Bit为单位来存储数据,因此在存储空间方面,可以大大节省。 /* 若 N =1 ; 申请内存空间为 int a[2] ; 假设需要排序或者查找的总数N=10000000,那么我们需要申请内存空间的大小为int a[1 + N/32],其中:a[0]在内存中占32为可以对应十进制数0-31,依次类推: 1.求十进制0-N对应在数组a中的下标: n/32 2.求0-N对应0-31中的数: N%32=M 3.利用移位0-31使得对应32bit位为1: 1<<M,并置1; 举例 : 如果想存储 3 (1) a下标 30/ 32 = 0 ; 放在a[0] 中; (2) 3% 32 = 30; (3) 左移 30 位 01000000 00000000 00000000 00000000 这个对应的值$a[0] = 1073741824 ; 1.求十进制0-N对应在数组a中的下标: 十进制0-31,对应在a[0]中,先由十进制数n转换为与32的余可转化为对应在数组a中的下标。比如n=24,那么 n/32=0,则24对应在数组a中的下标为0。又比如n=60,那么n/32=1,则60对应在数组a中的下标为1,同理可以计算0-N在数组a中的下标。 2.求0-N对应0-31中的数: 十进制0-31就对应0-31,而32-63则对应也是0-31,即给定一个数n可以通过模32求得对应0-31中的数。 3.利用移位0-31使得对应32bit位为1. 找到对应0-31的数为M, 左移M位:即2^M. 然后置1. 由此我们计算10000000个bit占用的空间: 1byte = 8bit 1kb = 1024byte 1mb = 1024kb 占用的空间为:10000000/8/1024/1024mb。 大概为1mb多一些。 */ class bigMap { //使用两个字节保存 private $mask = 0x1f ; private $bitsperword = 32 ; // 移位的位数为5 pow(2,5) = 32 private $shift = 5 ; // 存储数据的数组 public $bitArray = array(); /** $i 对应的数归零 */ function clearbit($i){ ////则将当前byte中的指定bit位取0,&后其他对方数组bit位必然不变,这就是 1 的妙用 // $i>>SHIFT 这里相当于 intval($i /32) ; // $i & $this->mask 这里相当于 $i % $this->mask ,取余 @$this->bitArray[$i >> $this->shift] &= ~(1<<($i & $this->mask)); } /** $i 对应的数致1 */ function setbit($i){ @$this->bitArray[$i >> $this->shift] |= (1<<($i & $this->mask)); } //test 测试所在的bit为是否为1 function testbit($i){ return $this->bitArray[$i >> $this->shift] & (1<<($i & $this->mask)); } } $oBig = new bigMap() ; $oBig->setbit(30) ; var_dump($oBig->testbit(2)) ; var_dump($oBig->bitArray) ; echo decbin($oBig->bitArray[0]),"<br>";

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