Precautions for using the array_merge() function in php array merging_PHP tutorial

 　　1.array_merge()合并

　　例子

 代码如下

$array = array('a'=>'bb');
$array2 = array('b'=>'cc');
$array3 = array_merge($array,$array2);

代码如下
$array = array('a'=>'bb'); $array2 = array('b'=>'cc'); $array3 = array_merge($array,$array2); 输出结果为 Array ( [a] => bb [b] => cc )

输出结果为

Array ( [a] => bb [b] => cc )

代码如下
$array = 1;//array('a'=>'bb'); $array2 = array('b'=>'cc'); $array3 = array_merge($array,$array2); print_r( $array3 );

　　上面因为都是数组就没有问题了，假如我们把$array 设置不是数组看看什么情况

代码如下
$array = 1;//array('a'=>'bb'); $array2 = array('b'=>'cc'); $array3 = array_merge($array,$array2); print_r( $array3 );

Results after operation

Warning: array_merge() [function.array-merge]: Argument #1 is not an array in E:test1.php on line 4

Tell us that we must have an array, then I have many ways to solve this,

　1. Use is_array() to make a judgment, but you will find that if there are too many arrays to merge, the judgments one by one are unreasonable. Later, I found that the data type can be converted

The code is as follows

$array = 1;//array('a'=>'bb');
$array2 = array('b'=>'cc');
$array3 = array_merge((array)$array,(array)$array2);
print_r( $array3 );

代码如下
$array = 1;//array('a'=>'bb'); $array2 = array('b'=>'cc'); $array3 =  array_merge((array)$array,(array)$array2); print_r( $array3 ); 输出结果不报错了 Array ( [0] => 1 [b] => cc )

The output results no longer report errors

Array ( [0] => 1 [b] => cc )

It automatically converts the number 1 into an array, so everyone must pay attention to these details when using it.

http://www.bkjia.com/PHPjc/816151.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/816151.htmlTechArticle

1.array_merge() merge example code is as follows $array = array('a'='bb'); $ array2 = array('b'='cc'); $array3 = array_merge($array,$array2); The output result is Array ( [a] = bb [b] = cc ) above...