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How to determine whether it is json data (format) in php_PHP tutorial

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Release: 2016-07-13 10:36:38
Original
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First of all, remember that json_encode returns a string, and json_decode returns an object.

Judge that the data is not in JSON format:

The code is as follows
 代码如下
function is_not_json($str){  
    return is_null(json_decode($str));
}
function is_not_json($str){

return is_null(json_decode($str));
}

 代码如下
function is_json($string) { www.111cn.net
 json_decode($string);
 return (json_last_error() == JSON_ERROR_NONE);
}

Judge whether the data is legal json data: (PHP version is greater than 5.3)

The code is as follows
function is_json($string) { www.111cn.net json_decode($string);

return (json_last_error() == JSON_ERROR_NONE);

}

The json_last_error() function returns errors that occurred during the data encoding and decoding process.* 解析json串
* @param type $json_str
* @return type
*/
function analyJson($json_str) {
$json_str = str_replace('\\', '', $json_str);
$out_arr = array();
preg_match('/{.*}/', $json_str, $out_arr);
if (!empty($out_arr)) {
$result = json_decode($out_arr[0], TRUE);
} else {
return FALSE;
}
return $result;
}
 代码如下

Note: The strings operated by json encoding and decoding must be UTF8.

Example
  • The code is as follows
    * Parse json string* @param type $json_str
  • * @return type
  • */
  • function analyzeJson($json_str) {
  • $json_str = str_replace('\\', '', $json_str);
  • $out_arr = array();
  • preg_match('/{.*}/', $json_str, $out_arr);
  • if (!empty($out_arr)) {
  • $result = json_decode($out_arr[0], TRUE);
  • } else {
  • return FALSE;
  • }
  • return $result;
  • }
  • If it is not json, return false
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http://www.bkjia.com/PHPjc/738511.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/738511.htmlTechArticleFirst of all, remember that json_encode returns a string, and json_decode returns an object. To determine if the data is not in JSON format: The code is as follows function is_not_json($str){ return is_null(json_decode...
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