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Example of PHP judging normal access and external access_PHP tutorial

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Release: 2016-07-13 10:39:13
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PHP determines normal access and external access

Copy code The code is as follows:

session_start();
if(isset($_POST['check'])&&!empty($_POST['name'])){
if($_POST['check'] == $_SESSION['check'] ){
echo "Normal access";
}else{
echo "External access";
}
}
$token = md5(uniqid(rand(),true) );
$_SESSION['check'] = $token;
?>




www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/732388.htmlTechArticlephp determines normal access and external access. Copy the code code as follows: ?php session_start(); if(isset($_POST ['check'])!empty($_POST['name'])){ if($_POST['check'] == $_SESSION['check']){ ec...
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