PHP custom function to calculate remaining time_PHP tutorial-PHP Tutorial-php.cn

PHP custom function to calculate remaining time_PHP tutorial

WBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWBOYWB

Release： 2016-07-13 10:49:12

Original

1187 people have browsed it

The remaining time refers to how many minutes or days it has been since an article was published. In many blog forums, you can see that the article was published 1 day ago. Below I will introduce two examples

Combine the two The string in date format is converted into a unix timestamp, and then subtracted to obtain the timestamp difference. Finally, judge the remaining time and generate a time format similar to (published 2 hours, 30 minutes and 20 seconds ago)

Then determine whether it is within 1 minute to one hour, that is, 60 seconds - 3600 seconds. If it is within, return X minutes. After getting the result, you need to use the remainder method to remove the minute part of the time, use % to take the remainder

The code is as follows

代码如下

复制代码

public function gettime($time_s,$time_n){
$time_s = strtotime($time_s);
$time_n = strtotime($time_n);
$strtime = '';
$time = $time_n-$time_s;
if($time >= 86400){
return $strtime = date('Y-m-d H:i:s',$time_s);
}
if($time >= 3600){
$strtime .= intval($time/3600).'小时';
$time = $time % 3600;
}else{
$strtime .= '';
}
if($time >= 60){
$strtime .= intval($time/60).'分钟';
$time = $time % 60;
}else{
$strtime .= '';
}
if($time > 0){
$strtime .= intval($time).'秒前';
}else{
$strtime = "时间错误";
}
return $strtime;
}

Copy code

public function gettime($time_s,$time_n){
$time_s = strtotime($time_s);
$time_n = strtotime($time_n);
$strtime = '';
$time = $time_n-$time_s;
if($time >= 86400){
return $strtime = date('Y-m-d H:i:s',$time_s);
}
if($time >= 3600){
$strtime .= intval($time/3600).'hour';
$time = $time % 3600;
}else{
$strtime .= '';
}
if($time >= 60){
$strtime .= intval($time/60).'minutes';
$time = $time % 60;
}else{
$strtime .= '';
}
if($time > 0){
$strtime .= intval($time).'seconds ago';
}else{
$strtime = "Wrong time";
}
return $strtime;
}

First determine whether the value you want to subtract is greater than the number of seconds in a day, 86400 seconds. If it is greater, return the time queried from the original database

Then determine whether it is within 1 hour to one day, that is, 3600 seconds-86400 seconds. If it is within, return X hours. After getting the result, you need to use the remainder method to remove the hour part of the time, use % to take the remainder

Finally determine whether it is within 1 minute, that is, 0 seconds - 60 seconds. If it is within 1 minute, return X minutes and seconds

http: //www.bkjia.com/PHPjc/632724.html

TechArticle

The remaining time refers to the minutes or days since an article was published. This is used in many blogs. Everyone in the forum has seen the article posted 1 day ago. Below I will introduce two examples...