Determine whether to pop up the pop-up window code based on whether the source is a search engine_PHP tutorial

Code:

$referer = $_SERVER['HTTP_REFERER'];
if(!$referer == ''){
if(ereg('http' . ['1'];< > If ($ Referer == 'Google' or Referer == 'Baidu') {
? & Gt;
& lt; script language = "javascript" & gt;
& lt;- <🎜 <🎜
window.open ('http://123.xia8.com', 'ad', 'height=600, width=800, top=0,left=0,toolbar=yes, menubar=yes, scrollbars=yes, resizable=yes, location=yes, status=yes')
//Write in one line
-->

                                                                                                                                                      .
}
}
?>
Usage: Modify the code, copy and insert it into the required PHP page.
Search engines can be added by themselves.





http://www.bkjia.com/PHPjc/631810.html

www.bkjia.com

truehttp: //www.bkjia.com/PHPjc/631810.htmlTechArticleCode: ?php $referer = $_SERVER['HTTP_REFERER']; if(!$referer == '' ){ if(ereg('http',$referer)){ $referer = @explode('.',$referer); if(is_array($referer)){ $referer = $referer['1'];. ..