PHP calculates the number of days between two dates

PHP calculates the number of days between two dates_PHP Tutorial

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Release： 2016-07-13 16:57:44

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This article will give students a detailed introduction to the example of calculating the number of days between two dates in PHP. Students can refer to it. We usually convert the date with strtotime and then calculate it, so that it can be accurate to hours, minutes and seconds. oh.

Example 1

Convert date directly

The code is as follows

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代码如下	复制代码
function daysbetweendates($date1, $date2){ $date1 = strtotime($date1); $date2 = strtotime($date2); $days = ceil(abs($date1 - $date2)/86400); return $days; }

function daysbetweendates($date1, $date2){

$date1 = strtotime($date1);

$date2 = strtotime($date2);

代码如下

复制代码

functionmaketime($date)
{
list($year,$month,$day) = explode('-',$date);
returnmktime(0,0,0,$month,$day,$year);
}
$date1 = '2007-01-08';
$date2 = '2007-03-01';
$d = (maketime($date2) - maketime($date1)) / (3600*24);
echo'相差$d 天';

$days = ceil(abs($date1 - $date2)/86400); Return $days; }

Example 2

The code is as follows	Copy code
functionmaketime($date)<🎜> {<🎜> list($year,$month,$day) = explode('-',$date);<🎜> returnmktime(0,0,0,$month,$day,$year);<🎜> }<🎜> $date1 = '2007-01-08';<🎜> $date2 = '2007-03-01';<🎜> $d = (maketime($date2) - maketime($date1)) / (3600*24);<🎜> echo'The difference is $d days';<🎜> <🎜>?>

Example 3

PHP implements calculation of year, month, week and day between two dates

The code is as follows

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Function format($a,$b){
                  //Check the size of two dates, the default is the smaller in the front and the larger in the back, if the front is larger and the back is smaller, swap the positions to ensure the front is small and the bottom is large
If(strtotime($a)>strtotime($b)) list($a,$b)=array($b,$a);
          $start = strtotime($a);
$stop = strtotime($b);
          $extend = ($stop-$start)/86400;
         $result['extends'] = $extend;
             if($extend<7){                                                                                                                                                                                                                                                                                                  $result['daily'] = $extend;
} Elseif ($ extend & lt; = 31) {// Back a weekly number of returns in less than 28 days. Because the leap year meets
If($stop==strtotime($a.'+1 month')){
                   $result['monthly'] = 1;
               }else{
                     $w = floor($extend/7);
$d = ($stop-strtotime($a.'+'.$w.' week'))/86400;
                   $result['weekly'] = $w;
                   $result['daily'] = $d;
            }
         }else{
$y=                if($y>=1){                                                                                                                                                                                                                                                                                   $start = strtotime($a.'+'.$y.'year');
$ A = date ('y-m-d', $ start);
                            // Determine whether it has really been a year, if not, then reduce it
If($start>$stop){
                            $a = date('Y-m-d',strtotime($a.'-1 month'));
                         $m =11;
                }
                     $extend = ($stop-strtotime($a))/86400;
            }
               if(isset($m)){
                     $w = floor($extend/7);
                     $d = $extend-$w*7;
               }else{
                      $m = isset($m)?$m:round($extend/30);
$stop>=strtotime($a.'+'.$m.'month')?$m:$m--;
                if($stop>=strtotime($a.'+'.$m.'month')){
                    $d=$w=($stop-strtotime($a.'+'.$m.'month'))/86400;
                    $w = floor($w/7);
                    $d = $d-$w*7;
                }
            }
            $result['yearly'] = $y;
            $result['monthly'] = $m;
            $result['weekly'] = $w;
            $result['daily']   = isset($d)?$d:null;
        }
        return array_filter($result);
    }

    print_r(format('2012-10-1','2012-12-15'));
?>