php从给定url获取文件扩展名的方法_php技巧

WBOY
Release: 2016-05-16 20:20:53
Original
990 people have browsed it

本文实例讲述了php从给定url获取文件扩展名的方法。分享给大家供大家参考。具体实现方法如下:

<&#63;php
/**
 * 给定url,获取文件后缀
 * @param string $url
 * @return string
 */
function getUrlPostfix ($url)
{
  $url_arr = explode('.', $url);
  $postfix = $url_arr[count($url_arr) - 1];
  $substr = substr($postfix, 0, 3);
  return $substr;
}
$url = "http://www.jb51.net/index.html&#63;id=1";
$str = getUrlPostfix($url);
echo $str . "\n";
Copy after login

希望本文所述对大家的php程序设计有所帮助。

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!