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Implement an Ajax-based survey program_PHP tutorial

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Release: 2016-07-13 17:32:44
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投票



(做为现在的主流开发语言)
include_once("server1.server.php(做为现在的主流开发语言)"); #servidor para Xajax(动态网站静态化)
$xajax(动态网站静态化)->printJavascript();
?>


 


(做为现在的主流开发语言)


global $db;

$poll = $db->getRow("select * from TBL_POLL order by poll_id desc limit 1");
$poll_id = $poll["poll_id"];
$pollitems = $db->getAll("select * from TBL_POLLITEM where poll_id=$poll_id");
?>



   (做为现在的主流开发语言) echo $poll["title"]; ?>

   (做为现在的主流开发语言) for ($i = 0, $count = count($pollitems); $i < $count; $i++) { ?>
  (做为现在的主流开发语言) echo $pollitems[$i][content] ?>

  (做为现在的主流开发语言) } ?>
 
 



服务器端

function poll($formData){
  global $db;
  $tmp="";
  $objResponse = new xajax(动态网站静态化)Response();
 
  $poll_id = $formData[poll_id];
  $pollitem_id = $formData[pollitem];
 
  if($pollitem_id > 0 && $poll_id > 0) {
   $db->query("update ".TBL_POLLITEM." set count=count+1 where pollitem_id = $pollitem_id");                 
  }
 
  $poll = $db->getRow("select * from TBL_POLL where poll_id = $poll_id");
  $pollitems = $db->getAll("select * from TBL_POLLITEM where poll_id=$poll_id");
 
 
  $tmp .="

".$poll["title"]."

";
    for ($i = 0, $count = count($pollitems); $i < $count; $i++) {
$tmp .="
".$pollitems[$i][content].": ".$pollitems[$i][count]."
";

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