PHP code to upload video_PHP tutorial
Jul 15, 2016 pm 01:21 PM
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>网页教学网(webjx.com)文件上传实例</title>
</head>
<body>
<form enctype="multipart/form-data" action='upfile.php' method=post>
<input type="hidden" name="MAX_FILE_SIZE" value="2000000000">
<input type=file name=upfile size=20>
<input type=submit value='上传文件'>
</form>
</body>
</html>
upfile.php.
<?php
function getname($exname){
$dir = "./uploadfile/";
$i=1;
if(!is_dir($dir)){
mkdir($dir,0777);
}
while(true){
if(!is_file($dir.$i.".".$exname)){
$name=$i.".".$exname;
break;
}
$i++;
}
return $dir.$name;
}
$exname=strtolower(substr($_FILES['upfile']['name'],(strrpos($_FILES['upfile']['name'],'.')+1)));
$uploadfile = getname($exname);
if (move_uploaded_file($_FILES['upfile']['tmp_name'], $uploadfile)) {
echo "<h2><font color=#ff0000>文件上传成功！</font></h2><br><br>";
}else {
echo "<h2><font color=#ff0000>文件上传失败！</font></h2><br><br>";
} echo "下面是文件上传的一些信息：<br><br>原文件名：".$_FILES['upfile']['name'] ."<br><br>类型：" .$_FILES['upfile']['type'] ."<br><br>临时文件名：".$_FILES['upfile']['tmp_name']. "<br><br>文件大小：".$_FILES['upfile']['size']."<br><br>错误代码：".$_FILES['upfile']['error'];
?>
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